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Alex Ar [27]
3 years ago
8

The weights of healthy adult male Labrador Retrievers are approximately Normally distributed with a mean of 77 pounds and a stan

dard deviation of 6 pounds
A)Make an accurate sketch of the weights of Labrador Retrievers with the horizontal axis marked

B)What weight would represent the 25th percentile?

C)What weight would represent the 75th percentile?

D) What is the interquartile range of male Labrador weights?

E)What proportion of male adult Labrador retrievers weigh above 85 pounds?

F) What proportion of male adult Labrador retrievers weigh between 60 and 80 pounds?

G) What proportion of male adult Labrador retrievers weigh less than 65 pounds?
Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:the photo is for part A.

B) the weight would be Invnorm(.25,77,6)=72.95

C)the weight would be 81.04 but this is the work invnorm(.75,77,6)=81.04

D)IQR=Q3-Q1

81.04-72.95=8.09

E)9.12 is the answer the work normalcdf(85,1000,77,6)=.0912

F).6892 or 68.92% are the answers the work normalcdf(60,80,77,6)=.6892

G).0227 or 2.27% is the answer and the work normalcdf(0,65,77,6)=.0227

Step-by-step explanation:

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Pls help me answer this !!
krek1111 [17]

We want our exponential function to look like

y = ab^x.

Let a = the initial y-value.

Our initial value is the first number given for f(x). So, a = 3.

Let b = the number that is needed to go from 3 to 6 to 12 to 24 to 48.

We find b by division.

So, b = the next number divided by the previous.

So, b = 6/3 = 2.

We now plug in our values into the general formula above.

y = ab^x

Answer: y = (3)(2)^x

4 0
3 years ago
Find the value of x x=
Georgia [21]
X=1 any number is equal to 1
5 0
3 years ago
A wheel on christine’s bicycle is 0.5 m in diameter christine races the bicycle for 50m how many times does the wheel turn as th
GarryVolchara [31]

Answer:

28.57

Step-by-step explanation:

3.14×0.5=1.750

50÷1.75=5000÷175 to eliminate the decimal points

5000÷175=28.571

then we round the answer to the nearest tenths

=28.57

8 0
3 years ago
Relationship B has a lesser rate than Relationship A. The graph represents Relationship A.
Zinaida [17]
Given that Relationship B has a lesser rate than Relationship A and that the graph representing Relationship A is a f<span><span>irst-quadrant graph showing a ray from the origin through the points (2, 3) and (4, 6) where the horizontal axis label is Time in weeks and the vertical axis label is Plant growth in inches.</span>

The rate of relationship A is given by the slope of the graph as follows:

slope= \frac{6-3}{4-2} = \frac{3}{2} =1.5

To obtain which table could represent Relationship B, we check the slopes of the tables and see which has a lesser slope.

For table A.
Time (weeks) 3 6 8 10
Plant growth (in.) 2.25 4.5 6 7.5

slope= \frac{4.5-2.25}{6-3} = \frac{2.25}{3} =0.75

For table B.
Time (weeks) 3 6 8 10
Plant growth (in.) 4.8 9.6 12.8 16

</span><span><span>slope= \frac{9.6-4.8}{6-3} = \frac{4.8}{3} =1.6

</span> For tabe C.
Time (weeks) 3 4 6 9
Plant growth (in.) 5.4 7.2 10.8 16.2

</span><span>slope= \frac{7.2-5.4}{4-3} = \frac{1.8}{1} =1.8

For table D.
Time (weeks) 3 4 6 9
Plant growth (in.) 6.3 8.4 12.6 18.9</span>

<span>slope= \frac{8.4-6.3}{4-3} = \frac{2.1}{1} =2.1</span>

Therefore, the table that could represent Relationship B is table A.
7 0
4 years ago
Read 2 more answers
Is 83 cm greater than or less than 1 m?
o-na [289]
IT'S OBVIOUSLY LESS THAN 1 M.
1 m = 100 cm
It's LESS.
6 0
3 years ago
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