Answer:
After 4 decades, the population of fishes in the pond becomes 48,000 fishes
Step-by-step explanation:
We are told to find the population of fishes in a pond after 4 decades given that the population of the pond doubles after each decade.
A decade is a period of 10 years
For the first decade, the population becomes 3,000 * 2 = 6,000 fishes
For the second decade, the population becomes 6,000 * 2 = 12,000 fishes
For the third decade, the population becomes 12,000 * 2 = 24,000 fishes
and lastly for the fourth decade, the population becomes 24,000 * 2 = 48,000 fishes
Answer:
-4, -3, 0, 2
Step-by-step explanation:
Answer:
796.00
Step-by-step explanation:
i dont know a random answer
Answer:
Option 4
Step-by-step explanation:
Term = n/(4^n)
(n+1)th term = (n+1)/[4^(n+1)]
Ratio: (n+1)/[4^(n+1)] ÷ n/(4^n)
= (n+1)/[4^(n+1)] × (4^n)/n
= [(n+1)/n] × (1/4)
For large n, (n+1)/n approaches 1
[(n+1)/n] × (1/4) approaches 1/4 which is less than 1
Since the ratio is less than 1, series converges