2x - z = 4
6x - 5z = 18
3z - 2w = -18
If u want me to solve them it’s
1. X = -2y + 12
2. x = 10 - 4/3y | for y, y = 15/2 - 3/4x
3. x = 2+ 1/2z | for z , z = -4 + 2x
4. x = 3 + 5/6z | for z , z = - 18/5 + 6/5x
5. W = -3/2x + 13/2 | for x , x = -2/3w + 13/3
6. x = -5w + 13 | w = -1/5x + 13/5
Let me help you, but first I will explain the formula used to calculate monthly compound interest.
The formula used to calculate compound monthly compound interest is
a=p(1+r/n)^nt
P Represents the principal
R Represents the rate (in decimal)
N is basically 12 months
T Represents the time (in years)
Let's plug the numbers in.
First statement
"His bank has offered him a loan at 13% interest for 36 months"
12000(1+.13/12)^(12)(3)
12000(1+.13/12)^(12)(3) = $17,686.64
Second statement
"12% interest for 60 months"
Plug in the numbers into the formula.
12000(1+.12/12)^(12)(5)
12000(1+.12/12)^(12)(5) = 21,000.36
<u>Answer</u>
The answer would be "13% interest for 36 months" as it is much lower compared to the other statement.
Multiply -3[4x+y=6].
This gets you -12x-3y=-18.
Add the two equations together to eliminate the y.
-12x - 3y = -18
+ 12x + 3y = 18
------------------------
0 = 0
This means that these are in fact the same line, therefore there are infinite solutions.