Answer:
The rate of decrease is 8%
Step-by-step explanation:
we know that
The general equation for the radioactive decay can be written as:
where
a is the amount in kilograms after time t.
a_0 is the original amount of the substance or y-intercept of the function
r is the decay rate, written in decimals.
t is the time
In this problem we have
so
solve for r
Convert to percentage
Answer:
The answer is below
Step-by-step explanation:
I have 14 Baseballs in 23 tennis balls. I bought some boxes of baseballs with 12 baseball to a box and equal amount of boxes of tennis balls with 16 balls to a box. write an expression to represent the total number of balls
Solution:
Let n represent the number of boxes of each type.
Given, the number of boxes of tennis = number of boxes of baseball, hence:
n = number of boxes of tennis = number of boxes of baseball.
Already I have 14 baseball and I bought boxes of baseballs with 12 baseball to a box, therefore:
Number of baseballs = 14 + 12n
I have 23 tennis ball and I bought boxes of tennis balls with 16 baseball to a box, therefore:
Number of tennis balls = 23 + 16n
Total number of balls = number of baseballs + number of tennis balls
Total number of balls = (14 + 12n) + (23 + 16n) = 14 + 23 + 12n + 16n = 37 + 28n
Total number of balls = 37 + 28n
Answer:
H0 : μ = 8.5
H1 : μ > 8.5
1 sample t test ;
Test statistic = 2.53
Pvalue = 0.994
No, we fail to reject the Null ;
There is no significant evidence to support the Claim that the mean running time of light bulb is greater Tha last year.
Step-by-step explanation:
H0 : μ = 8.5
H1 : μ > 8.5
Test statistic :
(xbar - μ) ÷ (s/sqrt(n))
(8.7 - 8.5) ÷ (0.5 / sqrt40)
Test statistic = 2.53
The Pvalue :
P(Z < 2.53) = 0.9943
Pvalue = 0.994
Decison region :
Reject H0 ; if Pvalue < α
0.9943 > 0.05 ; We fail to reject the Null
Answer:
(3) y = 4x
Step-by-step explanation:
In order for the equation not to change, the point (0, 0) must be on the original line and so on the line after dilation. The only equation with (0, 0) as a point on the line is y=4x.
Dilation about the origin moves all points away from the origin some multiple of their distance from the origin. If a point is on the origin, it doesn't move. We call that point the "invariant" point of the transformation. For the equation of the line not to change, the invariant point must be on the line to start with.
