Answer: 294.4 m²
<u>Step-by-step explanation:</u>
Separate the shaded region into two parts:
- The section containing the central angle of 230° (360° - 130°)
- The triangle with sides 11.1, 11.1 & 20.12 (use Law of Cosines)


Area of shaded region = Area of (1) + Area of (2)
= 247.3 + 47.1
= 294.4
Answer: d
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Step-by-step explanation:
The next number is 27.
You can find this by finding the common ratio between 3 and 9 and multiplying 9 by the common ratio. The common ratio is 3
Answer:
sorry agnor me
Step-by-step explanation:
plz egnore my ideodik nis
ticket sale on Saturday night is triple the ticket sale on Friday night.
Therefore
ticket sales on Saturday night = 3 x 12425 = 37275
Then
ticket sales for both nights = 12425 + 37275 = 49700
A ticket costs 35.
Let the number of people that attended the carnival on both nights be n.
Then, we have

Therefore 1420 people attended the carnival on both nights