Answer:
Part 1) The length of the diagonal of the outside square is 9.9 units
Part 2) The length of the diagonal of the inside square is 7.1 units
Step-by-step explanation:
step 1
Find the length of the outside square
Let
x -----> the length of the outside square
c ----> the length of the inside square
we know that

step 2
Find the length of the inside square
Applying the Pythagoras Theorem

substitute



step 3
Find the length of the diagonal of the outside square
To find the diagonal Apply the Pythagoras Theorem
Let
D -----> the length of the diagonal of the outside square




step 4
Find the length of the diagonal of the inside square
To find the diagonal Apply the Pythagoras Theorem
Let
d -----> the length of the diagonal of the inside square




Answer:
A) 7x^3 + 13x^2 + 8x + 9
Step-by-step explanation:
(3x^2 + 2x + 7x^3) + (10x^2 + 6x + 9)
I like to line them up vertically
7x^3 +3x^2 + 2x
+ (10x^2 + 6x + 9)
-----------------------------------
7x^3 +13x^2 +8x +9
Answer:
Whatever the length and width of the first triangle are take them and multiply by three. Place them in their respective sides of the new rectangle. The answer should be 9.
Step-by-step explanation:
Answer: -11s & -14t
Step-by-step explanation: