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irakobra [83]
3 years ago
9

Jane had a rectangular frame 30 inches in length and 24 inches in width. Stan made a similar frame that is smaller in size. Whic

h of the following could be the dimensions of the frame Stan made?
A. Length = 20inches, Width = 25inches
B. Length = 15inches, Width = 8inches
C. Length = 24, Width = 18inches
D. Length = 15inches, Width = 12inches
Mathematics
2 answers:
Veronika [31]3 years ago
3 0
The answer is D because it's half of First one...
Digiron [165]3 years ago
3 0
Hello! 

Let's multiply the length by the width first, so that we know how big the frame is. Then we can compare it to the other frame dimensions: 

A = l × w

A = 30 × 24 

A = 720

Now we know how big the frame is: 720 in²

Let's create frames using the dimensions from options A, B, C, and D. The frame has to be smaller in size, meaning it has to have an area less than 720 in²: 

Option A: 


A = l × w

A = 20 × 25 

A = 500 in²

Option B: 

A = l × w

A = 15 × 8 

A = 120 in²

Option C: 

A = l × w

A = 24 × 18 

A = 432 in²

Option D: 

A = l × w

A = 15 × 12

A = 180 in²

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Physics
Andrej [43]

Answer:

a) Josef jogging from A to B;

i. speed = 2 m/s

ii. velocity = 2m/s

a) a) Josef jogging from A to C;

speed = 1.9 m/s

ii. velocity = 2.2 m/s

Step-by-step explanation:

One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.

a) Josef jogging from A to B;

distance = 300 m

time = 2.5 seconds = 150 seconds

i. his average speed = \frac{distance}{time}

                               = \frac{300}{150}

                               = 2 m/s

ii. his average velocity = \frac{displacement}{time}

                               = \frac{300}{150}

                               = 2 m/s

b) Josef jogging from A to C,

distance = 300 + 100 = 400 m

time = 2.5 + 1 = 3.5 minutes

        = 210 seconds

i. his average speed = \frac{distance}{time}

                                  = \frac{400}{210}

                                  = 1.9 m/s

ii. his average velocity = \frac{\sqrt{V_{1} ^{2}   + V_{2} ^{2} } }{2}

V_{1} ^{2} = 4 m/s

V_{2} ^{2} = 1.9 m/s

his average velocity = \frac{\sqrt{4^{2} + 1.9^{2}  } }{2}

                                  = 2.2 m/s

5 0
3 years ago
How do I solve this problem
My name is Ann [436]
The answer will be 15/14, or 1 1/14 for the simplest form.
4 0
3 years ago
Read 2 more answers
Can you please help me with this i will give you a Brainiest
il63 [147K]

Answer:

Step-by-step explanation:

13

6 0
3 years ago
Read 2 more answers
A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The
zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200,  300

Let X be the total refund payment on the seven day cruise.

We can say  X = 0, if there is no rain on all 7 days.

P(X = 0) = _nC_x * P^x * (1 - P)n-x

P(X = 0) =  _7C_o * 0.2^0 * (1-0.2)^{7-0

P(X = 0) =1 * 1* (1-0.2)^{7

P(X = 0) =(0.8)^{7

P(X = 0) =0.2097152

If it rains on any one day; then X = 100

P(X = 100) = _nC_x * P^x * (1 - P)n-x

P(X = 100) =  _7C_1 * 0.2^1 * (1-0.2)^{7-1

P(X = 0) =7 * 0.2* (1-0.2)^{6

P(X = 100) =7* 0.2* (0.8)^{6

P(X = 100) =0.3670016

if it rains on any two day  ; then X = 200

P(X = 200) = _nC_x * P^x * (1 - P)n-x

P(X = 200) =  _7C_2 * 0.2^2 * (1-0.2)^{7-2

P(X = 200) =  21 * 0.2^2 * (0.8)^{5

P(X = 200) = 0.2752512

if it rains on any three day or more than that ; then X = 300

P(X \ge 300) = 1 - P(X < 300)  \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple[Var X] =E [X^2] - (E [X])^2

where;

E[X^2]  = \sum x^2 \times p \\ \\ E[X^2]  = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\  E[X^2]  = 0  + 3670.016 + 11010.048+ 13322.88  \\ \\  E[X^2]  =28002.944

(E [X]) = \sum x * p\\ \\  (E [X]) =  0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0
3 years ago
Complete the proof by providing the missing statement and reasons
Fittoniya [83]

Answer:

2. angle bisector splits into even halves

Step-by-step explanation:

that's all i can assist with sorry, proofs still confuse me!

3 0
3 years ago
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