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3 years ago

Complete the proof by providing the missing statement and reasons

Mathematics

1 answer:

Fittoniya [83]3 years ago

3 0

Answer:

2. angle bisector splits into even halves

Step-by-step explanation:

that's all i can assist with sorry, proofs still confuse me!

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A line passes through the points (-6,4) and (-2,2). Which is the equation of the line?

Art [367]

The answer is y= -1/2x + 1

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4 years ago

Read 2 more answers

if you draw one card from a standard deck, what is the probability of drawing a diamond or a red card?

Aleks [24]

Answer:

3/4 probability

probability to draw a red card = 11/26

probability to draw a diamond =1/4

probability of drawing one or other card = 35/52

# actually i am not sure

4 0

3 years ago

One-third of a storeâs inventory is childrenâs clothing. Two-fifths of its inventory is womenâs clothing. What fraction of the t

Eva8 [605]

Answer: C. 11/15

Step-by-step explanation:

Given : The fraction of stores inventory is children's clothing= $\dfrac{1}{3}$

The fraction of stores inventory is women's clothing= $\dfrac{2}{5}$

Since both events are independent.

Therefore, the fraction of the total inventory is children's or women's clothing = (Fraction of stores inventory is children's clothing ) + (Fraction of stores inventory is women's clothing )

$=\dfrac{1}{3}+\dfrac{2}{5}=\dfrac{5+2(3)}{15}$

$=\dfrac{11}{15}$

∴ The fraction of the total inventory is children's or women's clothing $=\dfrac{11}{15}$

Hence, the correct answer is C. 11/15 .

6 0

3 years ago

Which function is shown in the graph?

muminat

Answer: The correct answer choice is B

Step-by-step explanation:

I graphed each function on the desmos calculator and answer choice B matched the graph.

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3 years ago

F=e−yi−xe−yj is conservative. find a scalar potential f and evaluate the line integral over any smooth path c connecting a(0,0)

Alexxx [7]

If $\mathbf F$ is conservative, then there is a scalar function $f$ such that

$\nabla f(x,y)=\mathbf F(x,y)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j=e^{-y}\,\mathbf i-xe^{-y}\,\mathbf j$

Setting the first components equal to one another, we can integrate both sides to find

$\dfrac{\partial f}{\partial x}=e^{-y}\implies f(x,y)=xe^{-y}+g(y)$

Differentiating both sides with respect to $y$ gives

$\dfrac{\partial f}{\partial y}=-xe^{-y}+\dfrac{\mathrm dg}{\mathrm dy}=-xe^{-y}$
$\implies\dfrac{\mathrm dg}{\mathrm dy}=0$
$\implies g(y)=C$

so that

$f(x,y)=xe^{-y}+C$

By the fundamental theorem of calculus, we have that

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=\int_{\mathcal C}\nabla f\cdot\mathrm d\mathbf r=f(1,1)-f(0,0)=\frac1e$

4 0

3 years ago