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2 years ago

Select all that describe how the graph of y= -2cot(c+4)-3 differs from that of y= cot(x) brainly

Mathematics

2 answers:

malfutka [58]2 years ago

7 0

Answer:

Step-by-step explanation:

Shifted 3 units down

Stretched vertically

Shifted 4 units left

Alex17521 [72]2 years ago

5 0

Answer:

i) it is stretched vertically

ii) shifted 4 units to the left horizontally

iii) shifted 3 units down vertically

iv) reflected over x-axis

Step-by-step explanation:

y= -2cot(c+4)-3

Here -2 represents the vertical stretched

4 represents the horizontal shift.

-3 represents the vertical shift.

So the graph y = -2cot(c + 4) -3 differs from y = cot (x) in the following ways

i) it is stretched vertically

ii) shifted 4 units to the left horizontally

iii) shifted 3 units down vertically

iv) reflected over x-axis

Hope this will helpful.

Thank you.

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Find an equation for the perpendicular bisector of the line segment whose endpoints

TEA [102]

Answer:

y= -2x -8

Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

A perpendicular bisector is a line that cuts through the other line perpendicularly (at 90°) and into 2 equal parts (and thus passes through the midpoint of the line).

Let's find the gradient of the given line.

$\boxed{gradient = \frac{y1 -y 2}{x1 - x2} }$

Gradient of given line

$= \frac{1 - ( - 5)}{3 - ( - 9)}$

$= \frac{1 + 5}{3 + 9}$

$= \frac{6}{12}$

$= \frac{1}{2}$

The product of the gradients of 2 perpendicular lines is -1.

(½)(gradient of perpendicular bisector)= -1

Gradient of perpendicular bisector

= -1 ÷(½)

= -1(2)

= -2

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, we need to substitute a pair of coordinates that the line passes through into the equation. Since the perpendicular bisector passes through the midpoint of the given line, let's find the coordinates of the midpoint.

$\boxed{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2}) }$