y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
Step-by-step explanation:
Did you mean
Evaluate 3/2 + (-k) + (-2) where k = -5/2
= 3/2 - (-5/2) - 2
= 3/2 + 5/2 - 2
= 8/2 - 2
= 4 - 2
= 2
Answer:
im not sure bout it sorry mate.
Step-by-step explanation:
Answer:
11. c
12. c
Step-by-step explanation:
11. Since Angle RST = 60 degrees, Angle RTS = 60 degrees.
Triangle STU is a right triangle, so Angle STU and Angle SUT are both 45 degrees.
Angle RTS + Angle STU + Angle UTQ = 180 degrees
60 + 45 + Angle UTQ = 180
Angle UTQ = 180 - 105
= 75 degrees
12. Using the corresponding angles theorem, x = 45 degrees and y = 35 degrees.
x + y
45 + 35
80
Answer:1 sticker
Step-by-step explanation:because 56 is not a multiple of 6
