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3 years ago

10

tripp ran 4.8 times as many laps as tony. if tony ran 3.7 laps, how many laps did tripp run? how do i figure this out?

1 answer:

lana66690 [7]3 years ago

4 0

You multiply 3.7 by 4.8

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How do u do this?!?!

soldi70 [24.7K]

Answer:

-9

Step-by-step explanation:

5-p

p=-9

-4 is greater than 5-p

8 0

2 years ago

Solve: 5 + n > 2

tiny-mole [99]

$\\ \sf\longmapsto 5+n>2$

We have to find n
Take 5 to right side
sign will be changed

$\\ \sf\longmapsto n>2-5$

Simplify

$\\ \sf\longmapsto n>-3$

3 0

3 years ago

It is fall and time for joseph to harvest his farm. He currently has 120 acres of wheat. With the help of his farm equipment he

salantis [7]

A. Roc= 14a/d (he can harvest 14 acres per day) so to get 120 acres of wheat he would have to harvest wheat for a little over 5 and a half days

4 0

2 years ago

The probability of choosing a winning card from a stack of cards is 5.3%.

drek231 [11]

Answer:

94.7%

Step-by-step explanation:

If it is only winning or losing cards, then you can subtract 5.3 from 100 because probability is out of 100%

100-5.3 = 94.7

8 0

3 years ago

B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing

kenny6666 [7]

Answer:

$\boxed{ \boxed{ \sf {Marked \: price \: = Rs \: 1500}}}$

$\boxed{ \bold{ \boxed{ \sf{Selling \: price = \: Rs \: 1230}}}}$

Step-by-step explanation:

Let Cost price ( C.P ) be x

<u>Finding </u><u>the </u><u>Marked </u><u>price </u><u>and </u><u>selling </u><u>price </u>

Marked price = $\sf{x + 20\% \: of \: x}$

⇒ $\sf{x + \frac{20}{100} \times x}$

⇒ $\sf{ \frac{x \times 100 + 20x}{100} }$

⇒ $\sf{ \frac{120x}{100} }$ ⇒ ( i )

Selling price = $\sf{marked \: price \: - 18\% \: of \: marked \: price}$

⇒ $\sf{ \frac{120x}{100} - \frac{18}{100} \times \frac{120x}{100} }$

⇒ $\sf{ \frac{120x}{100} - \frac{54x}{250} }$

⇒ $\sf{ \frac{120x \times 5 - 54x \times 2}{500} }$

⇒ $\sf{ \frac{600x - 108x}{500} }$

⇒ $\sf{ \frac{492x}{500} }$ ⇒ ( ii )

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x </u><u>(</u><u> </u><u>Cost </u><u>price </u><u>)</u>

$\sf{loss = cost \: price - selling \: price}$

⇒ $\sf{20 = x - \frac{492x}{500} }$

⇒ $\sf{20 = \frac{x \times 500 - 492x}{500} }$

⇒ $\sf{20 = \frac{8x}{500} }$

⇒ $\sf{8x = 10000}$

⇒ $\sf{x = \frac{10000}{8} }$

⇒ $\sf{x = \: Rs \: 1250}$

Value of x ( cost price ) = Rs 1250

<u>Now</u><u>,</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>i </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>marked </u><u>price</u>

$\sf{marked \: price = \frac{120x}{100} }$

⇒ $\sf{ \frac{120 \times 1250}{100} }$

⇒ $\sf{ \: Rs \: 1500}$

<u>Replacing </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>ii </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>selling </u><u>price</u>

$\sf{selling \: price = \frac{492 \: x}{500} }$

⇒ $\sf{ \frac{615000}{500} }$

⇒ $\sf{ \: Rs \: 1230}$

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0

3 years ago