What is the range of the function O - O -8 O Osy O2 sy
1 answer:
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Answer:
f(x) = 3x⁴ - - 17x +
Step-by-step explanation:
To find f'(x), we will follow the steps below:
We will start by integrating both-side of the equation
∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx
f(x) = 3x⁴ - - 17x + C
Then we go ahead and find C
f(1) = 8
so we will replace x by 1 in the above equation and solve for c
f(1) = 3(1)⁴ - - 17(1) + C
8 = 3 - - 17 + C
C =8 - 3 + 17 +
C = 22 +
C =
C =
f(x) = 3x⁴ - - 17x +
Constant is the number that cannot change the value
Im not sure..but you can copy it