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gtnhenbr [62]
2 years ago
9

What's 30 times 2 and then add 6?

Mathematics
2 answers:
harina [27]2 years ago
5 0

Answer:

66

Step-by-step explanation:

just do 30 x 2 = 60 + 6 = 66

yuradex [85]2 years ago
3 0

30 times 2 is 60

add 6?

66! is the answer without the ! lol

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Marina walks from the police station at (-10, -4) to her friend Marissa’s house at (3, -8). She stops half way at a fast food re
Volgvan
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -10}}\quad ,&{{ -4}})\quad 
%  (c,d)
&({{ 3}}\quad ,&{{ -8}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{3-10}{2}~~,~~\cfrac{-8-4}{2} \right)
8 0
3 years ago
Please help!! I’ll give brainlist..!!
Xelga [282]

Answer:

the second, fourth, fifth, and sixth

4 0
3 years ago
Read 2 more answers
15. a music concert is organized at a memorial auditorium. the first row of the auditorium has 16 seats, the second row has 24 s
Drupady [299]

The equation for the nth term in the arithmetic sequence is   8n + 8.

The number of people that can be accommodated in the 16th row is 136.

<h3>What is an  arithmetic progression?</h3>

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

Given that,

No. of seats in first row = 16

No. of seats in second row = 24

No. of seats in third row = 32

Total number of rows = 50

It forms an arithmetic progression

First term = a = 16

common difference d = 8

Number of terms, n = 50

(A) The formula for the n th term of an arithmetic progression is given by

Tn = a + (n - 1) d

    = 16 + (n-1) 8

    = 16 + 8n - 8

Tn = 8n + 8

(B) Now,

n = 16

The number of seats in 16 th row is given by

T(16) = 8 x 16 + 8

T(16) = 136 seats

Hence, (A)The equation for the nth term in the arithmetic sequence is   8n + 8. and (B) The number of people that can be accommodated in the 16th row is 136.

To learn more about arithmetic progression  from the given link:

brainly.com/question/24205483

#SPJ4

4 0
1 year ago
(a) Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y? (b) In 2.00
Gemiola [76]

Answer:

A= 75686400

B= 7568640000

C= 75686400000

Step-by-step explanation:

1 day= 1440 min

1 year= 365 days

365 days*1440 min= 525600 min , 1 year= 525600 min

525600 min*2 years= 1051200 min

(in 2 years) 72 beats*1051200 min= 75686400

(in 200 years) 75686400*100= 7568640000

(in 2000 years) 7568640000*10 =75686400000

3 0
3 years ago
Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then
olchik [2.2K]

Answer:

It is proved that \frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Step-by-step explanation:

Given vector field,

F=P\uvec{i}+Q\uvec{j}+R\uvec{k}

Where,

P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}

To show,

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Consider,

\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}

\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}

Hence proved.

4 0
3 years ago
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