Analyze the diagram below and answer the question that follows.

Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passe

satela [25.4K]

Answer:

The probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

Step-by-step explanation:

The probability of a component passing the test is, P (S) = 0.79.

The probability that a component fails the test is, P (F) = 1 - 0.79 = 0.21.

Three components are sampled.

Compute the probability of the test result as SFS as follows:

P (SFS) = P (S) × P (F) × P (S)

$=0.79\times0.21\times0.79\\=0.131061\\\approx0.1311$

Compute the probability of the test result as SSF as follows:

P (SSF) = P (S) × P (S) × P (F)

$=0.79\times0.79\times0.21\\=0.131061\\\approx0.1311$

Thus, the probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

7 0

3 years ago

I need help on this question as soon as possible. If anybody can give me the correct answer I’ll give brainly. I just need help.

3241004551 [841]

Answer:

The solution of the system is (6, 9).

Step-by-step explanation:

Solve one of the variables and substitute the answer for the other variable.

Select one of the problems and solve for x.

3x+y=27

Subtract y from both sides.

3x+-y=27

Divide both sides by three.

x=1/3(-y + 27)

Multiply 1/3 by -y + 27.

x = -1/3y + 9

Replace -y/3 + 9 for x in the other problem 3x-2y=0.

3(-1/3y + 9) - 2y = 0

Multiply 3 by -y/3 + 9.

−y+27−2y=0

Add -y to -2y.

−3y+27=0

Subtract 27 from both sides of the problem.

−3y=−27

Divide both sides by −3.

y=9

Replace 9 for y in x=−1/3y+9.

x=−1/3*9+9

Multiply −1/3 times 9.

x=-3+9

Add 9 to -3.

x = 6.

x = 6, y = 9.

3 0

2 years ago

Look at the blank with the number 3

Umnica [9.8K]

Answer:

the answer is b

Step-by-step explanation:

the answer is b

8 0

2 years ago

One plane can travel 20 miles per hour faster than another. One of them goes 285 miles in the same time it takes the other to go

Hatshy [7]

Answer:

$\huge\fbox{Answer ☘}$

$\bold\blue{190 \:miles/hr \:and \:170 \:miles/hr}$

Step-by-step explanation:

Let the speed of faster plane be x

therefore ,

speed of slower plane = x - 20

As the time taken is same ,

$\frac{285}{x} = \frac{255}{x - 20} \\ \\ \frac{57}{x} = \frac{51}{x - 20} \\ \\ 57(x - 20) = 51x \\ \\ 6x = 1140 \\ \\ x = 190$

therefore ,

faster plane travels at a speed of 190 miles/hr

while..

the slower plane travels at a speed = ‎ ‎ ‎ ‎ ‎ ‎( 190-20 ) miles/hr

‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎=> 170 miles/hr

hope helpful~

7 0

2 years ago

Una compañía suministra electricidad. Cobra $100 mensuales fijos más 15 centavos por kilowatt hora. En los primeros 400 kilowatt

sweet [91]

Answer:

La función resultante es una función a trozos:

$C_{T}(x) = \left\{\begin{array}{cc}100+0.15\cdot x,\,0\le x \le 400\\112+0.12\cdot x,\,x> 400\\\end{array}$

Step-by-step explanation:

El coste total de la electricidad suministrada ( $C_{T}$ ), medida en pesos, es la suma del coste fijo ( $C_{F}$ ) y el coste variable ( $C_{V}$ ), medidas en pesos.

$C_{T} = C_{F}+C_{V}$ (1)

Ahora, tenemos que el coste fijo es $ 100 mensuales, así:

$C_{F} = \$ \,100$ (2)

Y el coste variable considera que se cobra 15 centavos por kilowatt-hora para los primeros 400 kilowatts-hora y 12 centavos por kilowatt-hora para cada kilowatt-hora que pase de 400 kilowatts-hora en el mes:

(i) Menos o igual que 400 kilowatts-hora:

$C_{V} = 0.15\cdot x$ (3)

Donde $x$ es la electricidad suministrada en kilowatts-hora.

(ii) Mayor que 400 kilowatts-hora:

$C_{V} = 0.15\cdot (400)+0.12\cdot (x-400)$

$C_{V} = 12+0.12\cdot x$

La función resultante es una función a trozos:

$C_{T}(x) = \left\{\begin{array}{cc}100+0.15\cdot x,\,0\le x \le 400\\112+0.12\cdot x,\,x> 400\\\end{array}$

3 0

3 years ago