Answer:
x=-3
Step-by-step explanation:
so you tryna get x by itself, so you are gonna do the opposite. so move nine over by subtracting it.
-9=3x
now you have to divide -9 by 3 to move it over
-2=x
Answer:
in the picture above.
Step-by-step explanation:
I hope that it's a correct answer.
Answer:
A 99% confidence interval will be wider than a 95% confidence interval
Step-by-step explanation:
From the question we are told that
The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm
Generally the width of a confidence interval is dependent on the margin of error.
Generally the margin of error is mathematically represented as
From the above equation we see that
Here 
is the critical value of the half of the level of significance and this value increase as the confidence level increase
Now if a 99% confidence level is used , it then means that the value of
will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval
Hence a 99% confidence interval will be wider than a 95% confidence interval
Answer:
B. 4 and 6 in
Step-by-step explanation:
The triangle inequality rule states: the length of a side of a triangle is less than the sum of the lengths of the other two sides and greater than the difference of the lengths of the other two sides.
So for the first qualification, we can eliminate A, C, and D. Therefore the answer is B, 4 & 6 in
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
