A rectangle whose perimeter is 110 feet. The length is 4 times as long as the width. Find the length and the width.
1 answer:
Set up a system of equations.
l=4w
2l+2w=110
Substitute l in to the second equation.
2(4w)+2w=110
8w+2w=110
10w=110
w=11
Substitute w back into the first equation.
l=4(11)=44
So, the length is 44 feet and the width is 11 feet.
Hope this helped!
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