Line BE and KE are the same length, so set the 2 equations to equal and solve for P.
7p+7 = 37-3p
Add 3 p to both sides:
10p +7 = 37
Subtract 7 from each side:
10p = 30
Divide both sides by 10:
p = 30/10
p = 3
The answer is B.
Multiple 1.65/100 which equals 14.4375
The add 14.4375 to 875 & round to the closest cent which is 889.44
3yds or 5yds is the closest
Answer:
Step-by-step explanation:
By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that
f'(c) = [f(6) - f(1)]/ (6 - 1)
So, f(6) - f(1) = 5f'(c).
Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20
So, f(6) - f(1) is between 10 and 20.
Answer: 1513.50=961.50+46x
The number of players the team can bring to the tournament = 12.
Step-by-step explanation:
Let x= the number of players the team can bring to the tournament.
Total money raised = Rent of bus + (Cost per player) (Number of players)

Hence, the number of players the team can bring to the tournament = 12.