The answer is 180 minutes. because you multiply 30 times 0.20 and you get 6. Then you multiply 6 times 30 and get 180 minutes. And 180 minutes in hours is 3 hours.
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
3
Step-by-step explanation:
3-x15 ?? Or 3-x+15 I’m not so sure I’m really bad at this but I really want to try to help I’m sorry if u got it wrong it would be my fault sorry
Total area of the rectangular land = 2^15 sq. miles
= 32768 sq. miles
total area of the pieces being sold = 8^3 sq. miles
= 512 sq. miles
now total no. of pieces = total area of the land / the area of samaller land that's being sold
= 32768 / 512
= 64
so the actual number of pieces is 64
