Answer:
26
Step-by-step explanation:
[(7+3)5-4]/2+3
-To solve this equation you have to use PEMDAS
P- Parentheses
E- Exponents
M- Multiplication
D- Division
A- Addition
S- Subtraction-
- With MD and AS you work left to right of the equation since they are in the same spot. (PE[MD][AS])
Step 1) [(10)5-4]/2+3
- First you do "P," parentheses, so you add 7+3=10
Step 2) [50-4]/2+3
- Next you do "M," multiplication, and multiply 10x5=50
Step 3) [46]/2+3
- Then you do "S," subtraction, and subtract 50-4=46
(FYI: Steps 1-3 were still in the parentheses. We had to start with the parentheses in the parentheses, work PEMDAS, and now we are out of the parentheses and have to work PEMDAS on the rest of the problem.)
Step 4) 23+3
- Now we do "D," division, and divide 46/2=23
Step 5) 23+3=6
- Finally we do "A," addition, and add 23+3=26 so the answer is 26
(FYI: "/" means division)
5y<7 <------- That is the answer. BTW (by the way) the variable needs to always be on the rights side.
Hope this helps!!!!!!!!!
Answer:
Approximately 313 cakes of similar size as those 50 cut from the smaller cake, can be cut from the bigger cake.
Step-by-step explanation:
The complete question is with the missing image of the cakes is attached to this solution.
From the image provided, the dimensions of the smaller cake = 2 ft × 1.6 ft
The dimensions of the larger cake = 5 ft × 4 ft
50 cakes are obtained from the smaller cake, how many cakes can be obtained from the bigger cake?
Area of the smaller cake = 2 × 1.6 = 3.2 ft²
Area of the bigger cake = 5 × 4 = 20 ft²
3.2 ft² cake provides 50 cakes.
20 ft² cake will provide (20×50/3.2) cakes = 312.5 cakes
Rounded to the nearest piece of cake = 313 cakes
Hope this Helps!!!
Answer:
200
Step-by-step explanation:
0.75X = 150
X = 200
so 200 is the answer
