Question

In Java; Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print a space after each seat, including after the last. Use separate print statements to print the row and column. Ex: numRows = 2 and numColumns = 3 prints:
1A 1B 1C 2A 2B 2C
import java.util.Scanner;
public class NestedLoops {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int numRows;
int numColumns;
int currentRow;
int currentColumn;
char currentColumnLetter;

numRows = scnr.nextInt();
numColumns = scnr.nextInt();

numColumns = currentColumnLetter
for(currentRow = 0; currentRow < numRows;currentRow++){
for(currentColumn = =

System.out.println("");
}
}

Answer 1

Answer:

import java.util.Scanner;

public class NestedLoops

{

public static void main(String[] args) {

 Scanner scnr = new Scanner(System.in);

       int numRows;

       int numColumns;

       int currentRow;

       int currentColumn;

       char currentColumnLetter;

       

       System.out.print("Enter number of rows: ");

       numRows = scnr.nextInt();

       System.out.print("Enter number of columns: ");

       numColumns = scnr.nextInt();

       

       for(int i = 1; i <= numRows; i++){

           currentColumn = 1;

           currentColumnLetter = 'A';

           for(int j = 1; j <= numColumns; j++){

               System.out.print("" + i + currentColumnLetter + " ");

               currentColumn++;

               currentColumnLetter++;

           }

       }

}

}

Explanation:

Ask user to enter the number of rows and columns.

Create a nested for loop, outer loop goes until numRows and inner loop goes until numRows.

Inside the first loop, set currentColumn to 1 and currentColumnLetter to 'A'. This way for after each row column value starts from 1 and letter value starts from A.

Insite the second loop, print the row value - i, and currentColumnLetter. Also,increment currentColumn and currentColumnLetter values by 1.