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DiKsa [7]
3 years ago
10

Nnbnnb dfhhfhfbhfbhdffd ddbhfbhdhfbhdhf hhffudjbfbjkd dbhdfbhbfhdb

Computers and Technology
1 answer:
saveliy_v [14]3 years ago
6 0
Tahheuend
Thatgeheh
Thahyateg
Fascinating
:)
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Which statement is unnecessary inside the unit test for the custom controller?
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A wizard is generally referred to as the tab sequence that contains the back button as well as the next button. It usually accepts information (i.e. data) from the inputs of users from different pages of the visualfoce as well as a variable from the previous website. The statement in option A is unnecessary for the application of the custom controller.    

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4 years ago
This is A C++ PROGRAM BTW!! Define a class named Money that stores a monetary amount. The class should have two private integer
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Jasminee accoo i'm very disappointed in you, this was a assignment that you were to do. Can you explain yourself?
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4 years ago
Write a program to have the computer guess at a number between 1 and 20. This program has you, the user choose a number between
ivanzaharov [21]

Answer:

This question is answered using C++ programming language.

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int num, computerguess;

   char response, hl;

   cout<<"Choose your number: ";

   cin>>num;

   srand((unsigned) time(0));

   int high = 20;    int low = 1;    int guess = 0;

   computerguess = low + rand() % high;

   cout<<"Is it "<<computerguess<<" ?y/n: ";

   cin>>response;

   while(response == 'n'){

       cout<<"Higher or Lower? h/l: ";

       cin>>hl;

       if(hl == 'h'){            low = computerguess+1; }

       else{   high = computerguess-1; }

       guess++;

       computerguess = low + rand() % high;

       cout<<"Is it "<<computerguess<<" ?y/n: ";

   cin>>response;

   }

   cout<<"I got your number of "<<num<<" in "<<guess+1<<" guesses.";

   return 0;

}

Explanation:

This declares num (user input) and computerguess as integer

   int num, computerguess;

This declares response (which could be yes (y) or no (n) and hl (which represents high or low) as char

   char response, hl;

This prompts user for input

   cout<<"Choose your number: ";

This gets user input

   cin>>num;

This allows the computer be able to generate different random numbers at different intervals

   srand((unsigned) time(0));

This declares and initializes the range (high and low) to 20 and 1 respectively. Also, the initial number of guess is declared and initialized to 0

   int high = 20;    int low = 1;    int guess = 0;

Here, the computer take a guess

   computerguess = low + rand() % high;

This asks if the computer guess is right

   cout<<"Is it "<<computerguess<<" ?y/n: ";

This gets user response (y or n)

   cin>>response;

The following iteration is repeated until the computer guess is right

   while(response == 'n'){

This asks if computer guess is high or low

       cout<<"Higher or Lower? h/l: ";

This gets user response (h or l)

       cin>>hl;

If the response is higher, this line gets the lower interval of the range

       if(hl == 'h'){            low = computerguess+1; }

If the response is lower, this line gets the upper interval of the range

       else{   high = computerguess-1; }

This increments the number of guess by 1

       guess++;

Here, the computer take a guess

   computerguess = low + rand() % high;

This asks if the computer guess is right

   cout<<"Is it "<<computerguess<<" ?y/n: ";

This gets user response (y or n)

   cin>>response;    }

This prints the statistics of the guess

   cout<<"I got your number of "<<num<<" in "<<guess+1<<" guesses.";

6 0
3 years ago
A form letter can be customized by using different fields in a __________.
alexgriva [62]
I think the answer to this is  C.email
4 0
3 years ago
Read 2 more answers
After 4th collision in ethernet, find the maximum time that the adapter waits until sensing the channel again for a 100 mbps bro
VARVARA [1.3K]

Waiting time for a 100 Mbps broadcast channel is 0.512 ms

Recall that with the CSMA/CD protocol, the adapter waits K * 512 bit times after a collision,

where K is drawn randomly. For K = 100,

The one bit time for 10 Mbps is 1/10000000 s = 0.0001 ms

The one bit time for 100 Mbps is 1/100000000 s = 0.00001 ms

Waiting time for a 10 Mbps broadcast channel is K*512*0.0001= 5.12 ms

Waiting time for a 100 Mbps broadcast channel is K*512*0.00001= 0.512 ms

<h3>What is a collision in Ethernet?</h3>
  • A collision happens on a half-duplex Ethernet network when two devices on the same network attempt to communicate data at the exact same time.
  • The two transmitted packets are "collapsed" by the network, which results in the network discarding both of them.
  • On Ethernets, collisions are unavoidable.
  • A collision is a momentary interaction between two bodies or more than two bodies at once that modifies the motion of the bodies involved as a result of the internal forces at work.
  • Collisions entail the application of force (there is a change in velocity).

Learn more about collision in Ethernet: brainly.com/question/14123270

#SPJ4

3 0
2 years ago
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