In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+
15) ∘ , and m∠KLM = (7x+9)^{\circ}(7x+9) ∘ . What is the value of x?
1 answer:
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Answer:
<h2>radius = 1.47 cm</h2>Step-by-step explanation:
Area of a circle = πr²
where
r is the radius
From the question
Area = 6.76 cm²
To find the radius substitute the value of the area into the above formula and solve for the radius
That's
Divide both sides by π
We have
r = 1.46689291
We have the final answer as
radius = 1.47 cm
Hope this helps you
