In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+
15) ∘ , and m∠KLM = (7x+9)^{\circ}(7x+9) ∘ . What is the value of x?
1 answer:
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Answer:
I think its D)
Step-by-step explanation:
7x−3y+2=0
Add -7x to both sides.
7x−3y+2+−7x=0+−7x
−3y+2=−7x
Add -2 to both sides.
−3y+2+−2=−7x+−2
−3y=−7x−2
Divide both sides by -3.
−3y /−3 = −7x−2 /−3
which equals d)
I also use this app to convert equations to slope-intercept and it showed me this
