In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+
15) ∘ , and m∠KLM = (7x+9)^{\circ}(7x+9) ∘ . What is the value of x?
1 answer:
Answer:
The value of x =10°
Step-by-step explanation:
Check attachment for solution.
Triangle theorem: the sum of the opposite interior angle is equal to the exterior angle.
<JKL+<LJK=<KLM
2x+14+3x+15=7x+9
Collect like terms
2x+3x-7x=9-14-15
-2x=-20
Divide both side by -2
x=10°
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