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Sphinxa [80]
3 years ago
6

In ΔJKL, \overline{JL} JL is extended through point L to point M, m∠JKL = (2x+14)^{\circ}(2x+14) ∘ , m∠LJK = (3x+15)^{\circ}(3x+

15) ∘ , and m∠KLM = (7x+9)^{\circ}(7x+9) ∘ . What is the value of x?

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

The value of x =10°

Step-by-step explanation:

Check attachment for solution.

Triangle theorem: the sum of the opposite interior angle is equal to the exterior angle.

<JKL+<LJK=<KLM

2x+14+3x+15=7x+9

Collect like terms

2x+3x-7x=9-14-15

-2x=-20

Divide both side by -2

x=10°

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Answer:

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ch4aika [34]

The correct equation is n - 31 = 52

To check the solution, substitute 83 for the variable in the equation

This is an addition problem.

To solve the equation, add 31 to both sides.

Step-by-step explanation:

A number decreased by thirty-one is fifty-two

That means:

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Assume that the number is n

∵ The number is n

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The correct equation is n - 31 = 52

∵ n - 31 = 52

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To check the solution, substitute 83 for the variable in the equation

This is an addition problem.

To solve the equation, add 31 to both sides.

Learn more:

You can learn more about solving equation in one variable in brainly.com/question/11306893

#LearnwithBrainly

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