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2 years ago

Reduce -34/87 to lowest terms.

Mathematics

2 answers:

sattari [20]2 years ago

8 0

It is already reduced.
They don't have a common factor to reduce them by.

scoray [572]2 years ago

3 0

I think it is already reduced.

How you a doin?

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Which of the tables represents a function?

Vanyuwa [196]

The answer is table D as it is the only one without a repeated input ❤️ hope that helps

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3 years ago

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What is 36.3 in % because i need help on test and teacher told me to get on this

saw5 [17]

3630 percent is your answer

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3 years ago

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I wish to digitally store a very old book written in an ancient Chinese language. What is the minimum number of megabytes (to th

Alisiya [41]

Answer:

The total number number of megabytes required to store the book is

Step-by-step explanation:

The smallest unit of storage on a computer are Bits. That is, a single on/off value.

This is different from a Bytes.

Bytes are often represented by the capital letter B, bits by a lower case b.

Please note: A single typed character (for example, 'x' or '8') is stored in one byte.

1 Byte = 8 bits.

1, 000 Bytes = 1 Kilobyte and

1,024 Kilobytes = 1 Megabyte

Therefore 1,000,000 Bytes = 1 Megabyte

STEP I - Get the Number of Bytes required.

Each symbol = 1 byte

Each Page has 445.8 symbols

The book has 360 pages.

Therefore, total number of symbols =

445.8 x 360

= 160, 488 Bytes

If our answer has to be in Megabytes, recall that 1,000,000 Bytes = 1 Megabyte.

Therefore the minimum number of megabytes required to store the book =

160,400/1,000,000

= 0.1604

In three decimal places our answer therefore is

= 0.160 Megabytes or 0.160MB.

Cheers!

8 0

2 years ago

PLEASE HELP IM RUNNING OUT OF POINTS

iVinArrow [24]

Answer: 16-p=C

Step-by-step explanation:

p is price of the wallet and it has to be either less than or equal to the 16 dollars spending money. And that result will equal C which represent the change or what's left after spending unknown amount from 16

4 0

3 years ago

You have two fair, six-sides dice. However, the dice have been modified so that instead or 1,2,3,4,5,6 the sides are numbered 1,

Tamiku [17]

Answer:

30.56%

Step-by-step explanation:

Let the sides on each dice be labeled as 1, 2a, 2b, 2c, 3, 4.

The sample space for the sum of the values being 4 is:

S={1,3; 3,1; 2a,2a; 2a,2b; 2a,2c; 2b,2a; 2b,2b; 2b,2c; 2c,2a; 2c,2b; 2c,2c}

There are 11 possible sums out of the 36 possible outcomes that result in a sum of 4. Therefore, the probability their total is 4 is:

$P(S) =\frac{11}{36}=0.3056 =30.56\%$

There is a 30.56% probability that their sum is 4.

6 0

3 years ago