$y=3x-4 \\
9x-3y=14 \\ \\
\hbox{substitute 3x-4 for y in the 2nd equation:} \\
9x-3(3x-4)=14 \\
9x-9x+12=14 \\
12=14 \\
not \ true \\ \\
\boxed{\hbox{no solution}}$

5 0

2 years ago

Helllllp it’s for my lil brother it’s in the pic attached

SSSSS [86.1K]

Answer:

chill out this this you post the 6 times

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.

Grace [21]

$\dfrac{n^2+n+1}{n-1}=\dfrac{(n-1)^2+3(n-1)+3}{n-1}=n-2+\dfrac3{n-1}$

The remainder term $\dfrac3{n-1}$ will never vanish, and will always be rational as long as the denominator is not 1, 3, or -3.

$n-1=1\implies n=2$
$n-1=3\implies n=4$
$n-1=-3\implies n=-2$

7 0

2 years ago