Kayla can bake 15 muffins in 2.5 hours. At this rate, how many can she bake in 8 hours?

Please Help I'll give brainliest

Alexandra [31]

Answer:

259.8

Step-by-step explanation:

6 0

3 years ago

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HELP ME PLEASE!!!

Komok [63]

Hope this helps you#!!

7 0

3 years ago

Jose's football weighs 7/8 pound. His football helmet weighs 5 1/6 pounds. Estimate how much more the helmet weighs than the foo

PtichkaEL [24]

Answer:

4 whole number, 7/24

Step-by-step explanation:

Thats correct i didnt had any explination because i wrote it on a paper

3 0

3 years ago

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The graph below shows the heights and arm spans of students in a classroom. Height and Arm Span of Students Based on the graph,

xxMikexx [17]

The best prediction of the height of a student with an arm span of 143 cm is 143 cm

Step-by-step explanation:

The missing graph is attached

The graph below shows the heights and arm spans of students in

a classroom

The x-axis represents the height in cm
The y-axis represents the arm span in cm

We need to find the height of a student with an arm span of 143 cm

∵ The graph does not contain the value of the given arm span

∴ We will use the line best fit (sold line in the attached graph) to find

the best predication of the height

∵ The line passes through points (150 , 150) and (160 , 160)

- The x-coordinates are equal the y-coordinate

∴ The equation of the line is y = x

∵ The arm span of a student is 143 cm

∵ y represents the arm span of a student

∴ y = 143

- Substitute the value of y in the equation of the line best fit

∵ y = x

∴ 143 = x

∵ x represents the height of a student

∴ The height of the student is 143 cm

The best prediction of the height of a student with an arm span of 143 cm is 143 cm

Learn more:

You can learn more about line best fit in brainly.com/question/8955867

#LearnwithBrainly

3 0

3 years ago

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What is the coordinates of the center of an ellipse defined by the equation 16x^2 + 25y^2 + 160x - 200y + 400 = 0 ? Please give

pickupchik [31]

16x^2 + 25y^2 + 160x - 200y + 400 = 0     Rearrange and regroup.

(16x^2 + 160x) + (25y^2 - 200y ) = 0-400.     Group the xs together and the ys together.

16(X^2 + 10x) + 25(y^2-8y) = -400.     Factorising.

We are going to use completing the square method.

Coefficient of x in the first expression = 10.

Half of it = 1/2 * 10 = 5. (Note this value)

Square it = 5^2 = 25.     (Note this value)

Coefficient of y in the second expression = -8.

Half of it = 1/2 * -8 = -4. (Note this value)

Square it = (-4)^2 = 16. (Note this value)

We are going to carry out a manipulation of completing the square with the values

25 and 16. By adding and substracting it.

16(X^2 + 10x) + 25(y^2-8y) = -400

16(X^2 + 10x + 25 -25) + 25(y^2-8y + 16 -16) = -400

Note that +25 - 25 = 0.    +16 -16 = 0. So the equation is not altered.

16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400

16(X^2 + 10x + 25) + 25(y^2-8y + 16) = -400 +16(25) + 25(16)    Transferring the terms -16(25) and -25(16)

to other side of equation. And 16*25 = 400

16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 25(16)

16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 400

We now complete the square by using the value when coefficient was halved.

16(x-5)^2 + 25(y-4)^2 = 400

Divide both sides of the equation by 400

(16(x-5)^2)/400 + (25(y-4)^2)/400 = 400/400              Note also that, 16*25 = 400.

((x-5)^2)/25 + ((y-4)^2)/16 = 1

((x-5)^2)/(5^2) + ((y-4)^2)/(4^2) = 1

Comparing to the general format of an ellipse.

((x-h)^2)/(a^2) + ((y-k)^2)/(b^2) = 1

Coordinates of the center = (h,k).

Comparing   with above   (x-5) = (x - h) , h = 5.

Comparing   with above   (y-k) = (y - k) , k = 4.

Therefore center = (h,k) = (5,4).

Sorry the answer came a little late. Cheers.

3 0

3 years ago