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Amanda [17]
3 years ago
11

Please help with number 27 thanks

Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0

Answer:

x = 4.4 repeating

Step-by-step explanation:

-14x+70 = 4x-10

Get like terms together

80 = 18x

Divide

x = 4.4 repeating

Ronch [10]3 years ago
4 0
This should be the answer to 27

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Is this answer correct?
ycow [4]
Yes. 25.6 is correct. And the written work looks great. Very thorough.
6 0
3 years ago
Read 2 more answers
Please, Help!
Veronika [31]

Answer:

adults = 40

children = 68

Step-by-step explanation:

Let the children=c

Let the adults = a

<em><u>Equations</u></em>

a + c = 108                 (1)

3.75a + 1.5c = 252    (2)

Multiply (1) by 1.5

1.5a + 1.5c = 162        (3)

Subtract (3) from (2)

3.75a + 1.5c = 252

1.5   a + 1.5c = <u>162</u>    Subtract

2.25a             = 90   Divide by 2.25

a = 90/2.25

a = 40

<em><u>Find the number of children</u></em>

a + c = 108

40 + c = 108

c = 108 - 40

c = 68

<em><u>Check</u></em>

LHS

3.75 * 40 + 1.50 * 68

150 + 102

252 Which checks with the right hand side.

7 0
3 years ago
⁻x₋5у₊z=17<br> ¬5x-5y+5z=5<br> 2x+5y-z=10
Pachacha [2.7K]

Step-by-step explanation:

they are not like variables and terms so u cant add them nor subtract term soit stays as it is

8 0
3 years ago
I recently (yesterday) took the AMC 10A, can anyone help me with this problem?
lianna [129]
First, we claim that \frac{10^n-1}{9} is the n-digit number with all digits equal to one.

Note that 10^n is a one followed by n zeroes, so subtracting one gives n nines.  Divide that number by nine and you get n ones, completing the proof.

Therefore, we have that A_n = a \frac{10^n - 1}{9}, B_n = b \frac{10^n-1}{9}, and C_n = c \frac{10^{2n} - 1}{9}.

Let x = 10^n.  Then, we have:

c \frac{x^2-1}{9} - b \frac{x-1}{9} = (a \frac{10^n - 1}{9})^2 = a^2 \frac{x^2 - 2x + 1}{81}.

Multiplying by 81 gives:

9c(x^2-1) - 9b(x-1) = a^2 (x^2-2x+1)

Now, note that x=1 is not a valid input, since 10^n = 1 requires n=0, so we safely divide by x-1 to get:

9c(x+1) - 9b = a^2(x-1)

9cx + 9c - 9b = a^2x - a^2

x(9c-a^2) = 9b-9c-a^2

Because this is now a linear equation in x, it has either zero, one, or infinitely many solutions.  Obviously, we need the latter to occur, which happens when 9c=a^2 and 9b-9c-a^2 = 0, since the coefficient of x must cancel to zero and thus the RHS must equal zero as well.

Since 9c = a^2, we must have a = 3 \sqrt{c}.  Since a must be a multiple of three, we plug in values.  If a = 9, we get c = 9 and thus 9b - 162 = 0, which is impossible.  So a = 9 doesn't work.

With a = 6, c = 4, and thus 9b-72=0, so 9b=72, so b=8.  This gives 6+8+4=18 as one possibility.

With a = 3, c = 1, and thus 9b - 18 = 0, so b = 2.  This obviously is worse.

We've gone through all the cases and the two possibilities are 2 and 18, so our answer is \boxed{18}.


8 0
4 years ago
What the equation for y.
nikklg [1K]

Answer:

A

Step-by-step explanation:

first move the 2x to the other side and you get 2y=4-2x, then you divide the entire equation by 2 and get y=2-x, which when re arranged is y = -x+2.

7 0
3 years ago
Read 2 more answers
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