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Keith_Richards [23]
3 years ago
13

Select all of the following that represent quadratic expressions:

Mathematics
1 answer:
suter [353]3 years ago
7 0
C. (x + 2)(x + 1)

it can be turned into an equation :)
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Find the equation of the line that passes through the points (-4, 2) and (1, -8). Use the form y=Mx+b
GuDViN [60]
ANSWER: Y=-2x-6

EXPLANATION:
(2- -8)/(-4-1)= 10/-5= -2

2=-2(-4) +b
2= 8 + b
b=-6
5 0
3 years ago
At the We-Pack Shipping, the workers can unload 28 trucks in 7 hours. Which of the following is a correct unit rate for this sit
boyakko [2]

Answer:

4 trucks per hour

Step-by-step explanation:

You would do the trucks over the hours to get the ratio so, 28:7 is equal to 4:1 because 28/7 = 4

5 0
3 years ago
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1 1/5 divided by /10
ZanzabumX [31]

Answer:

<u>0.12, 6/50</u> are the answers.

Step-by-step explanation:

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6 0
3 years ago
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A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
Use the double bar graph below to answer the following question.
natali 33 [55]

Answer:

the population would be 1,200,000 of San Diego in 2000

8 0
3 years ago
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