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3 years ago

Help me please I am lost

Mathematics

1 answer:

goblinko [34]3 years ago

7 0

Answer:

The answer to your question is:

a) f(a) -2 = a² - 3

b) f(a - 2) = a² - 4a + 3

c) f(b + d) = b² + 2bd + d² - 1

Step-by-step explanation:

a. f(a) - 2 = (a)² - 1 - 2

f(a) -2 = a² - 3

b. f(a - 2) = (a - 2)² - 1

f(a - 2) = a² - 4a + 4 - 1

f(a - 2) = a² - 4a + 3

c. f(b + d) = (b + d)² - 1

f(b + d) = b² + 2bd + d² - 1

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Max put 38,250 miles on his car during the three years that he owned it. At this rate, how many miles would be on his car after

saveliy_v [14]

Answer:

89,250 miles

Step-by-step explanation:

you divide 38,250 by 3 to get how many miles he drove a year, then multiply it by 7 for the seven years and you get 89,250 miles in 7 years.

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3 years ago

One number is 3 less than twice another. If their sum is 39 find the numbers

DedPeter [7]

Answer:

The numbers are 14 and 25

Step-by-step explanation:

Let one of the numbers be x. The second number we are told is 3 less than twice x. The second number will thus be;

2x - 3

The sum of the numbers is thus;

x + (2x - 3) = 3x - 3

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3 years ago

I still can’t figure out this stupid simple interest question! I tried several answer n NONE worked so I’m gonna try 1 last time

natka813 [3]

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2 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

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3 years ago

Look at the picture and you can get the brainliest if you get it right no links

Aleks04 [339]

The answer would be C

n+1.25=20

3 0

2 years ago