If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.
We are required to find the approximate margin of error.
Margin of error is the difference between calculated values and real values.
n=1488
p=0.69
Margin of error=z*
Z score when confidence level is 99%=2.576.
Margin of error=2.576*
=2.576*
=2.576*
=2.576*
=2.576*0.01198
=0.03088
Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.
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Answer:
(1, -6)
Step-by-step explanation:
the layout of your question is kind of confusing, but i'm guessing this is the system of equations
x = -y - 5
-3x + 7y = -45
plug in x to the second equation
-3(-y - 5) + 7y = -45
distribute
3y + 15 + 7y = -45
combine like terms
10y = - 60
divide by 10
y = -6
plug y into first equation
x = -(-6) - 5
x = 6 - 5
x = 1
<h2>x > 9</h2>
Step-by-step explanation:
<h3><em>-</em><em>5</em><em> </em><em>(</em><em>x</em><em>-</em><em>1</em><em>)</em><em> </em><em>></em><em> </em><em>-</em><em>4</em><em>0</em></h3><h3><em>-</em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em><em> </em><em>></em><em> </em><em>-</em><em>4</em><em>0</em></h3><h3><em>-</em><em>5</em><em>x</em><em> </em><em>></em><em> </em><em>-</em><em>4</em><em>0</em><em> </em><em>-</em><em>5</em></h3><h3><em>-</em><em>5</em><em>x</em><em> </em><em>></em><em> </em><em>-</em><em>4</em><em>5</em></h3><h3><em>x</em><em> </em><em>></em><em> </em><em>-</em><em>4</em><em>5</em><em> </em><em>÷</em><em> </em><em>-</em><em>5</em></h3><h3><em>x</em><em> </em><em>></em><em> </em><em>9</em></h3>
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C I took the tests on eg today
Answer:
-63
Step-by-step explanation:
-9 multiply by 7
