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kiruha [24]
3 years ago
9

Externally applied mechanical forces acting on a body, such as normal and shear forces, will cause deformation dependent on the

characteristics of that body and the magnitudes of the applied forces. Similarly, changes in temperature can cause deformation (i.e., expansion or contraction) as particles and bonds inside the material undergo changes in energy. For simple geometries, the changes in volume are proportional in the linear dimensions. Each of the 25cm×5cm25cm×5cm beams below is subjected to a 20 degree change in temperature. Rank the items based on the total change in length along the long axis of the beams. Many polymers such as polyethylene are significantly affected by changes in temperature, especially when compared to the metal and mineral materials discussed here. To a lesser degree, soft metals likewise are significantly affected by temperature changes. For example when heated, lead expands almost a third more than aluminum and almost twice as much gold. However, hard metals and materials, such as platinum and quartz, do not deform significantly in response to temperature. Because platinum is a metal, it will deform almost nine times more than quartz.

Mathematics
1 answer:
natima [27]3 years ago
8 0

Find the answer in the attachment

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When Laura was a store manager at a movie store, she made $500 a week. Ten years later, as a clothing store manager, she made $8
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Answer:

(800-500)/500 x 100

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Step-by-step explanation:

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Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio
Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

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3 years ago
The sum of two numbers is 63. The larger number is 23 more than the smaller number. What are the numbers?
Sunny_sXe [5.5K]

x+y=63

x=y+23

y+23+y =63

2y +23 = 63

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3 years ago
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Find the area of the shaded region.
lbvjy [14]

Answer:

48\pi\\\approx 150.796

Step-by-step explanation:

1.Approach

To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.

2.Find the area of the larger circle

The formula to find the area of a circle is the following,

A=(\pi)(r^2)

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. (\pi) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

A_l=(\pi)(r^2)\\A_l=(\pi)(8^2)\\A_l=(\pi)(64)

3.Find the area of the smaller circle

To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.

8 ÷2 = 4

Radius = 4

Substitute into the formula,

A_s=(\pi)(r^2)\\A_s=(\pi)(4^2)\\A_s=(\pi)(16)

4.Find the area of the shaded region

Subtract the area of the smaller circle from the area of the larger circle.

A_l-A_s\\=64\pi - 16\pi\\=48\pi

\approx150.796

5 0
3 years ago
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