Answer:
Add the equations in order to solve the first variable. Plug this value into the other equation in order to solve the remaining variables.
The point form is (3,-1)
The equation form is x = 3, y = -1
Hope this helps!
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Answer:
f(n) = -6n - 10.
Step-by-step explanation:
This is arithmetic sequence with first term a1 = -16 and common difference d = -6.
So f(n) = a1 + d(n - 1)
= -16 - 6(n - 1)
= -16 - 6n + 6
= -6n - 10.
Checking:
f(10) = -6(10) - 10 = -70.
5+5=10
15-5=10
5x2=10
20/2=10
10^1 (10 to the power of 1) or 0.1^-1 (0.1 to the power of -1)
If you have 2 functions, f(x) and g(x), you would find f(g(x)) and g(f(x)). If, after you simplify both and you end up with just "x" as the answer, they are inverses of each other. For example, f(x) = 3x - 2 and g(x) = (x+2)/3
f(g(x)) takes the g function and plugs it into the x in the f function, like this:
![f(g(x))=3[ \frac{(x+2)}{3} ]-2](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D3%5B%20%5Cfrac%7B%28x%2B2%29%7D%7B3%7D%20%5D-2%20)
cancel out the 3's to get
f(g(x))=(x+2)-2 which is just x. Now do it the other way: g(f(x))
![g(f(x))= \frac{[(3x-2)+2]}{3}](https://tex.z-dn.net/?f=g%28f%28x%29%29%3D%20%5Cfrac%7B%5B%283x-2%29%2B2%5D%7D%7B3%7D%20)
3x-2+2 is 3x, so we have

See?
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