Question

(2x^2/4x-8)×(x-6)(x+1)/x^5

Answer 1

$\frac{2x^{2}}{4x - 8} * \frac{(x - 6)(x + 1)}{x^{5}} = \frac{2}{4x - 8} * \frac{x^{2} - 5x - 6}{x^{3}} = \frac{2x^{2} - 10x - 12}{4x^{4} - 8x^{3}}$