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3 years ago

(2x^2/4x-8)×(x-6)(x+1)/x^5

1 answer:

5 0

$\frac{2x^{2}}{4x - 8} * \frac{(x - 6)(x + 1)}{x^{5}} = \frac{2}{4x - 8} * \frac{x^{2} - 5x - 6}{x^{3}} = \frac{2x^{2} - 10x - 12}{4x^{4} - 8x^{3}}$

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Carol has 1/4 of a sheet cake left. if she shares the remaining cake with her 3 friends, how much of the original cake will each

GuDViN [60]

Answer:

1/12 of the original

Step-by-step explanation:

If you split 1/4 into 3 equal pieces, then each friend gets 1/12 of the original cake

3 0

3 years ago

PLEASE HELP!!!

Oksanka [162]

Answer:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

Step-by-step explanation:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

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3 years ago

The largest possible fair dice is a disdyakis triacontahedron, which has 120 sides. What is the expected value, E(X), of rolling

Luden [163]

Assuming that the 120 faces have all numbers from 1 to 120 printed on them, we have a dice that can output all numbers between 1 and 120 with the same probability of 1/120.

So, the expected value is

$\displaystyle \sum_{i=1}^{120}i\cdot p(i) = \sum_{i=1}^{120}i\cdot \dfrac{1}{120}=\dfrac{1}{120}\sum_{i=1}^{120}i=\dfrac{1}{120}\dfrac{120\cdot 121}{2}=\dfrac{121}{2}=60.5$

5 0

3 years ago

What number has the same value as [5]

prohojiy [21]

<h2>Answer:</h2>

None. 5 is a PRIME NUMBER.

4 0

4 years ago

Solve the following system of equations by the substitution method.

ruslelena [56]

5x = y + 6 (I)
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 → $x = \frac{y+6}{5}$

Soon:
2x - 3y = 4 → $2* (\frac{y+6}{5}) - 3y = 4\to \frac{2y+12}{5} - 3y = 4$
<span>least common multiple (5)
</span> $\frac{2y+12}{5} - 3y = 4\to \frac{2y+12}{\diagup\!\!\!\!\!5} - \frac{15y}{\diagup\!\!\!\!\!5} = \frac{20}{\diagup\!\!\!\!\!5}$
$2y + 12 - 15y = 20$
$- 15y + 2y = 20 - 12$
$- 13y = 8$
$\boxed{\boxed{y = - \frac{8}{13} }}\end{array}}\qquad\quad\checkmark$

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4 years ago