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2 years ago

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Which statement best describes the area of Triangle ABC shown below? A triangle ABC is shown on a grid. The vertex A is on order

ed pair 3 and 5, vertex B is on ordered pair 4 and 1, and the vertex C is on ordered pair 2 and 1. It is twice the area of a square of side length 2 units. It is one-half the area of a square of side length 2 units. It is twice the area of a rectangle of length 2 units and width 4 units.

1 answer:

Alinara [238K]2 years ago

3 0

Answer:

( x , y ) = ( -1 , - 5 )

Step-by-step explanation:

This was the answer when i did it.

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I need help with this question. Please someone help me please.

aalyn [17]

I believe your answer would be B, Bisect AB, but not be perpendicular to it.

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3 years ago

50% of what number is 32?

andriy [413]

So you know 50% means half right? So then do 32*2 and you get 64.

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

Obi's age is twice oba's age 4 years ago obi was three times as old as oba. find their ages

frutty [35]

Answer:

Obi's age is 18 and Oba's age is 9

Step-by-step explanation:

Let Obi's age be x and Oba's age be y

<u><em>Condition 1:</em></u>

x = 2y -----------(1)

<u><em>Condition 2:</em></u>

(x-4) = 3(y-4)

=> x -4 = 3y-12

=> x - 3y = -9 -----(2)

<u><em>Putting eq (1) in (2)</em></u>

2y - 3y = -9

=> -y = -9

=> y = 9

Now,

x = 2y

=> x = 2(9)

=> x= 18

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6/7 divided by 12 or 12/1

aksik [14]

6/7 divided by 12/1 =
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