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Svetradugi [14.3K]
2 years ago
14

PLEASE HELP!!!

Mathematics
1 answer:
Oksanka [162]2 years ago
4 0

Answer:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

Step-by-step explanation:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

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An independent random sample is selected from an approximately normal population with an unknown standard deviation. Find the p-
Vedmedyk [2.9K]

The complete question is missing, so i have attached it

Answer:

A) Reject the null hypothesis

B) Reject the null hypothesis

C) Fail to reject the null hypothesis

D) Reject the null hypothesis

Step-by-step explanation:

A) We are given;

Ha: μ > μ_o (This is thus, a one-tail problem)

n = 11

T = 1.91

Using online p-value from t-score calculator as attached with a DF = n - 1 = 11 - 1 = 10, and t-value = 1.91, and significance level of 0.05, and 1 tail, we have;

The p-value is 0.042602

P-value is less than significance level, thus, we will reject the null hypothesis

B) We are given;

Ha: μ < μ_o (This is thus, a one-tail problem)

n = 17

T = -3.45

Using online p-value from t-score calculator as attached with a DF = n - 1 = 17 - 1 = 16, and t-value = 1.91, and significance level of 0.05, and 1 tail, we have;

The p-value is  0.001647

P-value is less than significance level, thus, we will reject the null hypothesis

C)We are given;

Ha: μ ≠ μ_o (This is thus, a two-tail problem)

n = 7

T = 0.83

Using online p-value from t-score calculator as attached with a DF = n - 1 = 7 - 1 = 6, and t-value = 0.83, and significance level of 0.05, and 2 tail, we have;

The p-value is 0.438308.

P-value is higher than the significance level, thus, we will fail to reject the null hypothesis.

D) We are given;

Ha: μ > μ_o (This is thus, a one-tail problem)

n = 28

T = 2.13

Using online p-value from t-score calculator as attached with a DF = n - 1 = 28 - 1 = 27, and t-value = 2.13, and significance level of 0.05, and 1 tail, we have;

The p-value is 0.021218

P-value is lower than the significance level, thus, we will reject the null hypothesis

P-value is lower than the significance level, thus, we will reject the null hypothesis.

6 0
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7 0
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Nine more than the quotient of a number and two
wariber [46]
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Samantha had 11/12 of a cup of sugar. She used 5/12 of a cup of sugar to bake muffins. How much sugar, in cups, does Samantha ha
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Answer:

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Step-by-step explanation:

11/12-5/12=6/12=1/2

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