Question

Which shows the graph of the solution set of 3y – 2x > –18?

Answer 1

Were are the graphs?

Answer 2

Answer:

$3y-2x>-18$

Step-by-step explanation:

We are given with a linear equation  $3y-2x> -18$ . We have to draw this inequality.

In order to draw this inequality , we have to first draw the graph of

$3y-2x= -18$

Let us do it , by converting the equation into intercept form, and find the x and y intercepts.

Divide both side, each term by -18 , we get

$\frac{3y}{-18}-\frac{2x}{-18}= \frac{-18}{-18}$

$\frac{y}{-6}-\frac{x}{-9}= 1$

$\frac{y}{-6}+\frac{x}{9}= 1$

$\frac{x}{9}+\frac{y}{-6}= 1$

Hence our x intercept = 9

y intercept = -6

Hence the line passes through the coordinates (9,0) and (0,-6). We now plot them on graph and draw our line.

Now we have to check which region to shade.

Our inequality is given as $3y-2x>-18$

Let us see whether (0,0) satisfies this inequality. For that we need to substitute them in our equation.

$3(0)-2(0)>-18$

$0-0>-18$

$0>-18$

Which is true .

Hence , we shade the region which is containing (0,0) . Also our line need to be broken as it is containing > sign in it.