Answer:

Step-by-step explanation:
step 1
In the isosceles right triangle PQT
PQ=PT ----> because is an isosceles triangle
Applying the Pythagoras Theorem
we have


substitute the values



step 2
In the square QRST

step 3
In the right triangle RSU
Applying the Pythagoras Theorem

we have


substitute the values and solve for SU





X=3,-1 the roots are the (zeros)
Answer:
Step-by-step explanation:POOHSHIESTYDATSMYDAWGBUTPOOHYKIMREALLYSHIESTY
We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
Answer:
(0.55, 0.75)
Step-by-step explanation:
The range can be estimated to be 6 standard deviations wide. Therefore, the standard deviation is:
σ = (0.72 - 0.42) / 6
σ = 0.05
The margin of error is ±2σ, so:
ME = ±0.10
Therefore, the interval estimate is:
(0.65 - 0.10, 0.65 + 0.10)
(0.55, 0.75)