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stich3 [128]
3 years ago
5

Collect data from all your family members and write down their heights (in cm).

Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

mode : the value that appears most frequently in a data set

mean : te everage of all number

median : the middle number in a sorted, ascending or descending

range : the difference between the largest and smallest numbers.

ANSWER ;

mode : none

mean : 145.4 ( you need to add all the number and divide by how many your family member)

median : 159

range : 80 ( the largest - the smallest)

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<h3><u>Given</u><u>:</u></h3>

line m || line n

<h3><u>To</u><u> </u><u>Find</u><u>:</u></h3>

The value of x.

<h3><u>Alternate</u><u> </u><u>Interior</u><u> Angles</u><u>:</u></h3>

The angles formed when a transversal intersects two parallel lines ( m and n ).

<h3><u>Explan</u><u>ation</u><u>:</u></h3>

6x + 10° = 5x + 28° ( Alternate Interior Angles )

By transposition method, we get

6x - 5x = 28° - 10°

By simplifying the like terms, we get

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5 0
3 years ago
What are the two whole numbers closest to square root of 95
Rzqust [24]
The square root of 95 is 5 of5

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3 years ago
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If lines l and m are parallel, then 2 and 3 are corresponding angles.<br>True or false
enyata [817]
The answer is false
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3 years ago
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A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What
Gnesinka [82]

Given:

Endpoints of a line segment AB are A(2,3) and B(8,11).

To find:

(1) Slope of AB.

(2) Length of AB.

(3) Midpoint of AB.

(4) Slope of a line perpendicular to AB.

Solution:

We have, endpoints of line segment AB, A(2,3) and B(8,11).

(1)

Slope of AB is

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{11-3}{8-2}

m=\dfrac{8}{6}

m=\dfrac{4}{3}

Therefore, the slope of AB is \dfrac{4}{3}.

(2)

Length of AB is

AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(8-2)^2+(11-3)^2}

AB=\sqrt{(6)^2+(8)^2}

AB=\sqrt{36+64}

AB=\sqrt{100}

AB=10

Therefore, the length of AB is 10 units.

(3) Midpoint of AB is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{2+8}{2},\dfrac{3+11}{2}\right)

Midpoint=\left(\dfrac{10}{2},\dfrac{14}{2}\right)

Midpoint=\left(5,7\right)

Therefore, the midpoint of AB is (5,7).

(4)

Product of slopes of two perpendicular lines is -1.

Let the slope of line perpendicular to AB be m₁.

m_1\times \dfrac{4}{3}=-1

m_1=-\dfrac{3}{4}

So, slope of line perpendicular to AB is -\dfrac{3}{4}.

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3 years ago
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