based on sample one, how many students from the entire student population preferred the 8:30 am start time

denis23 [38]

Additive Inverse of 63 = -63
Since the additive inverse of 63 is -63, additive inverse is also known as the opposite number.

3 0

3 years ago

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which statement correctly compares two values? a)the value of the 7 in 37.596 is 1/10 the value of the7 in 26.74 b) the value of

Andrews [41]

The value of 7 in 26..74 is 0.7

The value of 7 in 37.596 is 7.

1/10 the value of 7 in 26.74 is 0.07 and 0.07 ≠ 7.

So, statement a) is incorrect.

1/100 the value of 7 in 26.74 is 0.007 and 0.007 ≠ 7.

So, statement c) is incorrect.

100 times the value of 7 in 26.74 is 70 and 70 ≠ 7.

So, statement d) is incorrect.

10 times the value of 7 in 26.74 is 7 and 7 = 7.

So, statement b) is correct and it correctly compares two values.

7 0

2 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Mrs. Barnes cuts1/2 of a piece of construction paper. She uses 1/6

denpristay [2]

Answer:

Step-by-step explanation:

what fraction?? she uses 1/6 of the construction paper

if you are referring to how much paper is left, its 2/6 aka 1/3

4 0

1 year ago

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What is the charge on an object that has 1. 25 * 10 ^-17.

Aliun [14]

Answer: To determine the charge on an object, determine the number of excess protons or excess electrons. Multiply the excess by the charge of an electron or the charge of a proton - 1.6 x 10-19 C.

Step-by-step explanation:

7 0

2 years ago

based on sample one, how many students from the entire student population preferred the 8:30 am start time​

based on sample one, how many students from the entire student population preferred the 8:30 am start time