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3 years ago

Cos³x.tan²x - cosx = ?

Mathematics

1 answer:

melamori03 [73]3 years ago

4 0

tan x = sin x/cos x

cos³ x *tan²x - cos x = cos³x *(sin²x/ cos² x) - cos= cosx*sin²x - cos x =

= cos x(sin² x - 1) = - cos x(1 - sin²x)= - cosx*cos²x = - cos³ x

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Hello!

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2 years ago

The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°

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Answer:

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Step-by-step explanation:

Given:

m<BQS = 80°

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3 years ago

Read 2 more answers