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Alina [70]
3 years ago
6

Cos³x.tan²x - cosx = ?

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

tan x = sin x/cos x

cos³ x *tan²x - cos x = cos³x *(sin²x/ cos² x) - cos= cosx*sin²x - cos x =

= cos x(sin² x - 1) = - cos x(1 - sin²x)= - cosx*cos²x = - cos³ x

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Write two formulas for the area of a triangle
kotegsom [21]

Answer:

Hi mate your answer is

Step-by-step explanation:

Area of traingle equal 1/2×base×height

We have divided by two this is because you know the are of a rectangle is base + height but a triangle is like cut rectangle into two half pieces of you look carefully than to make any traingle a rectangle you will have to take another on opposite side so that's why we divide it by two

If you need further help plz ask

8 0
4 years ago
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Brainliest please help!
Dmitriy789 [7]

Answer:

120

Step-by-step explanation:

6 x 6 = 36

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4 0
3 years ago
Let m,n,p, and q represent nonzero positive integers. find a number in terms of m,n,p, and q that is halfway between m/n and p/q
alukav5142 [94]
This is the same as averaging. You add them and divide by 2.

((m/n) + (p/q))/2 would be a number in between m/n and p/q.

Do note that n and q must be nonzero, but luckily that is a given.
7 0
3 years ago
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Can anyone help me with this question ? 6c + 3 =45
ikadub [295]

Answer:

Ans: 6c+3=45

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7 0
3 years ago
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How many different menus showing 10 main courses can a restaurant make if it has 15 main courses from which to choose? 360,360 3
PtichkaEL [24]

Answer:

3003

Step-by-step explanation:

The number of differents menus containing 10 main courses that the restaurant can make if it has 15 main courses from which to chose is calculated through the combination: 15C10. The formula of the combination is: nCr = n! / ((r!) x(n - r)!) 

Where r=10 and n=15

Substituting the values to the equation: 15C10 = 15! / (10!)x(10 - 5)! = 3003

Then there are 3003 different menus that a restaurant can makeif it has 15 main courses from which to choose.

5 0
3 years ago
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