Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
B is the right answer for this
Answer:
axis of symmetry x=3/2
vertex (3/2, 0)
Step-by-step explanation:
to find the axis of symmetry we use h = -b/2a
where ax^2 + bx+c
h = -(-12)/2(4)
h= 12/8
h = 3/2
the axis of symmetry is x = 3/2
the x coordinate of the vertex is h x=3/2
to find k, the y coordinate of the vertex, substitute x=3/2 into the equation
y=4x^2-12x+9
y=4(3/2) ^2-12(3/2)+9
= 4 (9/4) - 6*3 +9
= 9-18+9
= 0
the vertex (3/2, 0)
The formula for volume is Length x width x height.
Bottom: 18 * 12 * 8 = 1728 cubic centimeters.
Middle: 12 * 8 * 6 = 576 cubic centimeters.
Top = 4 *4*4 = 64 cubic centimeters.
Total: 1728 + 576 + 64 = 2368 cubic centimeters.
