This is a common factor problem.
Pencils come in a pack of 12
Erasers come in a pack of 10
First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3
So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers
I hope this helps. Let me know if you have any questions!!
To find if a point is a solution to a system of equations, we need to plug in the x and y values of the point into each equation, and see if the equation is true.
Let's plug it into the first equation first:
-2(3) - 4(-2) might = 2
-6 + 8 = 2
The first equation is true.
Now, we need to check the second equation:
3(3) + 4(-2) might =8
9 - 8 does not = 8
Therefore, even if the point satisfies one equation, it does not satisfy the other. We can conclude that this is not a solution.
Hope this helps!
Answer:
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Answer:
{1, -9, 56, -269}
Step-by-step explanation:
Evaluate the rule for n=2, 3, and 4 in sequence.
For n=2
f(2) = (-5)f(1) +11 = (-5)(4) +11 = -9
f(3) = (-5)f(2) +11 = (-5)(-9) +11 = 56
f(4) = (-5)f(3) +11 = (-5)(56) +11 = -269
The first four terms of the sequence are {1, -9, 56, -269}.
30 is greater than 3. So 30 > 3
