Answer: Do you have answer choices?
Explanation:
Answer:
B. It was necessary that each of the two phage components, DNA and protein, be identifiable upon recovery at the end of the experiment.
Explanation:
Hershey and Martha Chase used radiolabeled the DNA of some of the bacteriophage cells with phosphorus (32P). They radiolabeled the sulfur (35S) of the coat protein in the second batch of the phage cells. They infected some of the bacterial cells with phage having radiolabeled DNA while the other <em>E. coli</em> cells were infected with the phage carrying radiolabeled coat protein. This allowed the clear identification of the radiolabelled molecule (DNA or protein) present in the host cell.
They observed that the <em>E. coli </em>cells infected with phage having radiolabeled DNA exhibited the radioactivity while the other batch of the host cell did not show it.
Answer:
umm is this a staement or a question
Explanation:
Large predators are found at higher trophic levels because specialized bodies are needed to extract the small energy that gets to them.
The energy that gets to successive trophic levels decreases progressively because much of it is lost as heat. This means that a small percentage of the energy from the producers that form the bases of trophic levels to the predators that are somewhat at the top of trophic levels.
With big body size, the bodies of predators are organized into systems that work together to efficiently extract the small energy that gets to them from immediate lower trophic level.
More on the energy from trophic levels can be found here: brainly.com/question/13375401?
