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1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
2.
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
Step-by-step explanation:
y-y1 = m(x-x1)
y-4 = 2(x-3)
y-4=2x-6
y= 2x -6+4
y=2x-2
The answer is 25 degrees.
This is how you solve the equation, first you must know that the straight like ABC=180, DBC is 130, so the remaining amount is 50 degrees, BE is a bisector of ABD which means it splits ABD right down the middle. So ABE+EBD=50 degrees, 25+25=50 since both sides MUST be equal in order for BE to be a bisector of ABD.
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268 gallons are remaining. The equation would be y=324-7x, with x being 8. 7(8) is 56, and then you take away 56 from 324, which then gives you 268 gallons remaining