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3 years ago

What is the slope of the line that contains the points (-4,2) and (6,-3)?-

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

Answer:

Step-by-step explanation:

the formula is $\frac{y_{2}-y_{1} }{x_{2} -x_{1}}$

When we plug that in we get $\frac{-3-2}{6- (-4)} = \frac{-5}{10} = -\frac{1}{2}$

Hope this helps!

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Total Points: 50

Sveta_85 [38]

Answer:

1. slope

2.Positive

3.up and down

4. Left and right

5. 1/1 or over 1 up 1

Step-by-step explanation:

7 0

3 years ago

Given: f(x) = 3x2 + 2x – 1

denis-greek [22]

Answer:

Step-by-step explanation:

f(x) = 3x^2 + 2x – 1

Let x=5

f(5) = 3(5)^2+2(5) -1

= 3*25 +10-1

= 75+10 -1

= 85 -1

4 0

3 years ago

Write a in slope-intercept form of the line that passes threw (-9,5) and (-3,3)

Amanda [17]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

We have the following points:

$(x_ {1}, y_ {1}): (- 9,5)\\(x_ {2}, y_ {2}): (- 3,3)$

Substituting we have:

$m = \frac {3-5} {- 3 - (- 9)}\\m = \frac {-2} {- 3 + 9}\\m = \frac {-2} {6}\\m = - \frac {1} {3}$

Thus, the equation is of the form:

$y = - \frac {1} {3} x + b$

We substitute one of the points and find "b":

$3 = - \frac {1} {3} (- 3) + b\\3 = 1 + b\\3-1 = b\\b = 2$

Finally, the equation is of the form:

$y = - \frac {1} {3} x + 2$

Answer:

$y = - \frac {1} {3} x + 2$

7 0

3 years ago

Which ordered pair makes both inequalities true Y<-x+1 Y>x

goldfiish [28.3K]

Answer:

x = -1 ; y = 1

Step-by-step explanation:

x = -1

y = 1

Plug in the corresponding numbers to the corresponding variables:

y < -x + 1

(1) < -(-1) + 1

1 < 1 + 1

1 < 2 (True)

y > x

1 > -1 (True).

7 0

3 years ago

How does the graph of g(x) = <img src="https://tex.z-dn.net/?f=%28x%2B12%29%5E%7B2%7D" id="TexFormula1" title="(x+12)^{2}" alt="

Law Incorporation [45]

Answer:

Horizontal translation of the parent graph

Step-by-step explanation:

<h2>Definitions:</h2>

In the vertex form of a quadratic function, f(x) = a(x - h)² + k, where:

(h, k) = vertex of the graph

a = determines the width and direction of the graph's opening.

A horizonal translation to the parent graph is given by, y = f(x - h), where:

h > 0 ⇒ Horizontal translation of h units to the right

h < 0 ⇒ Horizontal translation of |h | units to the left

In the graph of g(x) = (x + 12)², the vertex occurs at point (-12, 0).

While the vertex of the parent graph, f(x) = x² occurs at point, (0, 0).

<h2>Answers:</h2>

Since the vertex of g(x) occurs at point, (-12, 0), substituting the value of (h, k ) into the vertex form will result into:

g(x) = a(x - h)² + k

g(x) = [x - (-12)]² + 0

g(x) = (x + 12)² + 0

g(x) = (x + 12)²

Therefore, the graph of g(x) = (x + 12)² represents the horizontal translation of the parent graph, f(x) = x², where the graph of g(x) is horizontally translated 12 units to the left.

3 0

2 years ago