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forsale [732]
3 years ago
12

What is 1/6 divided by 2

Mathematics
2 answers:
77julia77 [94]3 years ago
4 0
1/6 divided by 2

Keep, change, flip

1/6 * 1/2 = 1/12

Answer: 1/12
MaRussiya [10]3 years ago
4 0
The answer to this one can be :

1/12
or
0.0833333

You might be interested in
3 points
garri49 [273]

Answer:

j=8

Step-by-step explanation:

30-6=24 divived by 3 = 8 which means jordans age is 8 and matthew is 16

5 0
2 years ago
The ratio of the measures of the sides of a triangle is 8: 15: 17, and its perimeter is 480 in.. Find the measure of the shortes
lubasha [3.4K]

Answer:

96

Step-by-step explanation:

The ratio of the measure of sides of a triangle are 8:15:17

The perimeter is 480

8x + 15x + 17x= 480

40x= 480

x = 480/40

x = 12

Therefore the measure of the shortest side of the triangle can be calculated as follows

8x

8×12

= 96

6 0
3 years ago
what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil
dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
2 years ago
5 • (- 10) x = 100 Esse número apagado foi <br><br> (A) 2<br> (B) 20<br> (C) -5<br> (D) -257*
Anettt [7]
The answers is A
Explanation ;)
4 0
2 years ago
Please help me with this question. Please!
erica [24]
150=i^2
150^.5=12.2474
11^2=121
12^2=144
13^2=169
between 12 and 13, D
8 0
3 years ago
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