Question

A circle with radius 3 has a sector with a central angle of 60. What is the area of the sector?

Answer 1

Step-by-step explanation:

$central \: \angle \: ( \theta) = 60 \degree \\ radius \: (r) = 3 \: units \\ \\ area \: of \: sector \\ = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ = \frac{ 60 \degree}{360 \degree} \times 3.14 \times {(3)}^{2} \\ \\ = \frac{ 1}{6} \times 3.14 \times 9 \\ \\ = 3.14 \times 1.5 \\ \\ = 4.71 \: {units}^{2} \\ \\ \purple{ \bold{area \: of \: sector = = 4.71 \: {units}^{2}}}$