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Neporo4naja [7]
3 years ago
14

Josh​ simplified 4x - 8x ÷ 2 and said the answer was -2x. What was josh's error? What should his answer have been?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Given

4x - 8x ÷ 2

Under the rules of PEMDAS , division must be performed before subtraction.

Hence

4x - 8x ÷ 2 = 4x - 4x ← dividing - 8x by 2, then

4x - 4x = 0 ← correct answer

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Write the product as a sum: 14cos(39x)sin(19x)
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Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) - sin(20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

4 0
3 years ago
A Sum of $14 is made of 92 coins consisting of dimes and quarters. How Many are there of each kind of coin
steposvetlana [31]
So first I would say, what if all of them were dimes, how far away would it be from $14?

So 92 coins * 10 cents = $9.20

So it's 4.80 dollars away from 14 dollars.

So if we were to switch one to a quarter, it would increase by 0.15 cents.

So we want to see how many increases we need to reach 4.80 dollars more.

4.80/0.15 = 32

So there are 32 quarters and 60 dimes.
7 0
3 years ago
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I need help completing this answer are you available
melomori [17]

Answer:

Step-by-step explanation:

7 0
2 years ago
Which lists all the integer solutions of the equation |x| = 10?
kakasveta [241]

There is no list and no choices given.

The solutions of     | x | = 10   are   x = 10  and   x = -10 .
 
All (both) solutions happen to be integers.
There are no other solutions.

5 0
3 years ago
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igor_vitrenko [27]
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3 years ago
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