"how long..." is asking for time (t). "The amount of time spent in the air" is the time from when the ball was kicked (0 seconds) to the time it landed on the ground. Need to find the x-intercepts (one will be negative which will be invalid). You can do this by factoring ... <em>or by using the quadratic formula.</em> With the equation you provided, it is not factorable, so you must use the quadratic formula.
h = -16t² + 60t + 3
a=-16 b=60 c=3
![t = \frac{-b +/- \sqrt{b^{2}-4ac } }{2a}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-b%20%2B%2F-%20%5Csqrt%7Bb%5E%7B2%7D-4ac%20%7D%20%7D%7B2a%7D)
![t = \frac{-60 +/- \sqrt{60^{2}-4(-16)(3) } }{2(-16)}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-60%20%2B%2F-%20%5Csqrt%7B60%5E%7B2%7D-4%28-16%29%283%29%20%7D%20%7D%7B2%28-16%29%7D)
![t = \frac{-60 +/- \sqrt{3600 + 192} }{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-60%20%2B%2F-%20%5Csqrt%7B3600%20%2B%20192%7D%20%7D%7B-32%7D)
![t = \frac{-60 +/- \sqrt{3792} }{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-60%20%2B%2F-%20%5Csqrt%7B3792%7D%20%7D%7B-32%7D)
![t = \frac{-60 +/- 61.6}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-60%20%2B%2F-%2061.6%7D%7B-32%7D)
or ![t = \frac{-60 - 61.6}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-60%20-%2061.6%7D%7B-32%7D)
or ![t = \frac{-121.6}{-32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-121.6%7D%7B-32%7D)
t = -0.05 or t = 3.8 <em>disregard the negative</em>
Answer: 3.8 seconds
Answer:
20x^4 - 13x^3 + 8x^2- x + 6
Step-by-step explanation:
box method :)
Answer: He does have enough.
Explanation: Simplifying 7/8 cups to fourths you get 1 3/4 cups of milk. If he has 2 cups of milk he still would have 1/4 cup left over of milk.
Answer:
-2x + 8
Step-by-step explanation:
I applied the distribution technique to the original question.