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olganol [36]
3 years ago
9

A bottling plant produces bottles of 500 ml at the production rate of 10,000 bottles per hour. An inspector randomly picks up 10

0 bottles every 15 minutes and checks for quality. With visual inspection he finds a bottle either good or defective. In last 8 samples, the number of defective bottles that he found are: 0, 0, 2, 1, 0,1, 2 and 0. What are the upper and lower control limits of the corresponding p-chart?
a 0.82,0.18
b. 0.099.0
C.12.1, 0
d. 1.31, 0.06
e.none of these
Mathematics
1 answer:
galben [10]3 years ago
6 0

Answer:

e.none of these

Step-by-step explanation:

Computations For CC for Fraction defective

Sample No  d  p=d/100

1                    0       0

2                    0      0

3                    2     0.02

4                     1     0.01

5                     0      0

6                     1      0.01

7                     2      0.02

8                     0        0

                 Total   0.06

\overline{p} =\frac{1}{k}\sum p=\frac{0.06}{8} =0.0075

\overline{q} =1- 0.0075= 0.9925

3 sigma control limits for p chart are given by:

\overline{p} \pm 3\sqrt{\overline{p}\overline{q}/n}\Rightarrow 0.0075\pm 3\sqrt{\frac{0.0075*0.9925}{100}}

= 0.0075\pm0.0259\Rightarrow ( 0.0334,0 )

hence option e is correct

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