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Sloan [31]
3 years ago
8

If you add the year of my birth to this year, subtract the year of my 20th birthday and the year of my 85th birthday, and then a

dd my present age, the result is 49. How old is she?
Mathematics
1 answer:
Bas_tet [7]3 years ago
7 0
It's not possible for the result to be 49
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Need help with #1 #4 #7 plz giving 15 points
valentina_108 [34]

Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

$ \implies - p - 24 = 9 $

$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

We get: $ \frac{d - 44}{11} = - 13 $

$ \implies d - 44 = - 13 \times 11 = - 143 $

$ \implies d = - 143 + 44 $

$ \implies \textbf{d} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 99} $

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$ \implies 5t - 4t = - 1 - 12 $

$ \implies (5 -4)t = - 13 $

$ \implies \textbf{t} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Hence, the answer.

7 0
3 years ago
Someone please answer this lol xx
Tamiku [17]
The answer is 4 lol
3 0
3 years ago
Annie and him are taking turns driving on their trip. On one day they drove a total of 420 miles. Annie drove 3 times farther th
JulijaS [17]
1,260 miles all you have to do is 420x3 because Annie drove 3 times faster.
3 0
3 years ago
When I'm 64
NemiM [27]
Chucks age=C
Dave’s age=x

C=x-3
6 0
2 years ago
A theater group holds a fund-raiser. It sells 100 raffle tickets for $7 apiece. Suppose you purchase four tickets. The prize is
lys-0071 [83]

Answer:

Check Explanation

Step-by-step explanation:

The random variable X is the possible net amount that leaves or enters one's hands. It is the amount of winnings!

X can take on value of -($7 × 4) = -$28

(That is, none of the four raffle tickets bought is picked to win)

X can also take on value of [$150 - ($7 × 4)] = $122

(That is, one of the four raffle tickets bought is picked to win)

For the probability distribution function, we find the probabilities of the different amount of winnings.

First of, probability of losing = (96/100) = 0.96

Then, probability of winning = (4/100) = 0.04

Probability density distribution is then given as

X | probability

-$28 | 0.96

$122 | 0.04

To go a step further, expected winnings would be

E(X) = Σ xᵢpᵢ = (-28)(0.96) + (122)(0.04)

= -26.88 + 4.88 = -$22

The expected winnings show that this is not a risk worth taking.

Hope this Helps!!!

4 0
2 years ago
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