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svlad2 [7]
3 years ago
5

Which factors can be multiplied together to make the trinomial 5x2 + 8x – 4? Check all that apply. (x + 1) (2x + 1) (x + 2) (5x

+ 1) (5x – 2) Mark this and return Save and Exit
Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

(5x-2) and (x+2)

Step-by-step explanation:


aivan3 [116]3 years ago
3 0

Answer:

the factors are (5x-2)  and (x+2)

Step-by-step explanation:

5x^2 + 8x – 4

first we multiply 5  and -4= -20

product is -20  and sum is +8

find out two factors whose product is -20 and add upto +8

10 * (-2) = 20

10 +(-2)= 8

5x^2 +10x-2x – 4

group the terms and factor out GCF

(5x^2 +10x)+(-2x – 4)

5(x+2) -2(x+2)

(5x-2)(x+2)

the factors are (5x-2)  and (x+2)

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Natalka [10]
Multiplying 20×1/2 is the same as dividing 20 by 2. Which means the answer is 10.
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In 2015 Michael purchased a stock for $45.80 a share. During the year he received $1.71 per share in cash dividends. At the end
timama [110]
Michael's initial investment is $45.80, the cost of the share. 
Michael Receives $1.71 in dividends.
He receives $47.50 for the stock when he sells it.
His profit on the sale of the stock is $47.50 - 45.80 = $1.70.
His total return on the stock is his total earnings, the dividends plus his profits on the sale of the stock, divided on what he paid initially, $45.80:
(1.71 + 1.70) ÷ 45.80 = .0744 = 7.45%
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Closest answer is 7.7%, not sure why it isn't exactly 7.45 or 7.5%. 

Answer is B) 7.7%
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3 years ago
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I hope this helps you



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4 0
3 years ago
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Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

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Naily [24]

Answer:

$3.23

Step-by-step explanation:

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9.5% × 34 = 3.23

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