Answer:
A. 5
Step-by-step explanation:
just use calculator tbh
Answer:
150
Step-by-step explanation:
Multiply 3 x 5 x 10
Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
-
, where
and
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴
and ![x_{2}=5](https://tex.z-dn.net/?f=x_%7B2%7D%3D5)
∴
and ![y_{2}=-3](https://tex.z-dn.net/?f=y_%7B2%7D%3D-3)
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = ![\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%285-%28-4%29%29%5E%7B2%7D%2B%28-3-3%29%5E%7B2%7D%7D%3D%5Csqrt%7B%285%2B4%29%5E%7B2%7D%2B%28-6%29%5E%7B2%7D%7D)
∴ HJ = ![\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665](https://tex.z-dn.net/?f=%5Csqrt%7B%289%29%5E%7B2%7D%2B36%7D%3D%5Csqrt%7B81%2B36%7D%3D%5Csqrt%7B117%7D%3D10.81665)
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units