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kupik [55]
3 years ago
8

Assume that blood pressure readings are normally distributed with a mean of 118 and a standard deviation of 6.4. If 64 people ar

e randomly​ selected, find the probability that their mean blood pressure will be less than 120. Round to four decimal places. A. 0.9938 B. 0.8615 C. 0.9998 D. 0.0062
Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

Option A - 0.9938

Step-by-step explanation:

Given : Assume that blood pressure readings are normally distributed with a mean of 118 and a standard deviation of 6.4. If 64 people are randomly​ selected.

To find : The probability that their mean blood pressure will be less than 120?

Solution :

The formula to find the probability is

P(Z=X)=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Where, X is the sample mean

\mu=118 is the population mean

\sigma=6.4 is the standard deviation

n=64 is the number of sample

The probability that their mean blood pressure will be less than 120 is given by,

P(Z

P(Z

P(Z

P(Z

From the z-table the value of z at 2.5 is

P(Z

Therefore, Option A is correct.

The probability that their mean blood pressure will be less than 120 is 0.9938.

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\begin{gathered} \qquad{\longrightarrow{\sf{Sum \:  of  \: all \:  angles =  {180}^{\circ}}}}\\\\ \qquad{\longrightarrow{\sf{{74}^{\circ} +  {52}^{\circ} + 18u =  {180}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{{126}^{\circ} + 18u =  {180}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{18u =  {180}^{\circ} -  {126}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{18u =  {54}^{\circ}}}}\\\\\qquad{\longrightarrow{\sf{u = \dfrac{54}{8}}}}\\\\\qquad{\longrightarrow{\sf{u =  {3}^{\circ}}}}\\\\ \qquad\star{\underline{\boxed{\frak{\pink{u =  {3}^{\circ}}}}}}\end{gathered}

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