Answer:
x=0
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Answer:
y = (3/2)x + 11
Step-by-step explanation:
We can start from the point slope form of a linear function:
(y-y1)=m(x-x1)
The slope m can be determined from the points given as m = (y2-y1)/(x2-x1)=(8-2)/(-2-(-6))=6/4=3/2
Then use either of the given points as x1, y1 to complete the equation (I picked the point (-6,2):
y-2=(3/2)(x+6)
You can rearrange this to:
y = (3/2)x + 11
The odds are defined as the probability it will occur divided by the odds it won’t. the probability it will is 3:6 probability it won’t is 3:6 decide those to get 1:2
Answer:
Rs. 18000
Step-by-step explanation:
![x(1 + 25\%) \: (1 - 15\%) - x = 900](https://tex.z-dn.net/?f=x%281%20%2B%2025%5C%25%29%20%5C%3A%20%20%20%281%20-%2015%5C%25%29%20-%20x%20%3D%20900)
![1.0625x - x = 900](https://tex.z-dn.net/?f=1.0625x%20-%20x%20%3D%20900)
![0.0625x = 900](https://tex.z-dn.net/?f=0.0625x%20%3D%20900)
![x = 14400](https://tex.z-dn.net/?f=x%20%3D%2014400)
•••••
![14400 \times (1 + 25\%)](https://tex.z-dn.net/?f=14400%20%5Ctimes%20%281%20%2B%2025%5C%25%29)
![\: \: \: \: \: \: \: \: = 14400 \times 1.25](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%3D%2014400%20%5Ctimes%201.25)
![\: \: \: \: \: \: \: \: =Rs. 18000](https://tex.z-dn.net/?f=%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%3DRs.%2018000)
The marked price of a calculator is ![\boxed{\green{Rs. 18000}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cgreen%7BRs.%2018000%7D%7D)
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]
Answer:
Yes they are
Step-by-step explanation:
In the triangle JKL, the sides can be calculated as following:
=> JK = ![\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B%281-2%29%5E%7B2%7D%20%2B%20%281-5%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B%28-1%29%5E%7B2%7D%2B%28-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B1%2B16%7D%3D%5Csqrt%7B17%7D)
=> JL = ![\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%285-2%29%5E%7B2%7D%20%2B%20%282-5%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B3%5E%7B2%7D%2B%28-3%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B9%2B9%7D%3D%5Csqrt%7B18%7D%20%3D%203%5Csqrt%7B2%7D)
=> KL = ![\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B%285-1%29%5E%7B2%7D%20%2B%20%282-1%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B4%5E%7B2%7D%2B1%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B1%2B16%7D%3D%5Csqrt%7B17%7D)
In the triangle QNP, the sides can be calculate as following:
=> QN = ![\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-3-%28-4%29%5D%5E%7B2%7D%20%2B%20%280-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B1%5E%7B2%7D%2B%28-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B1%2B16%7D%3D%5Csqrt%7B17%7D)
=> QP = ![\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-7-%28-4%29%5D%5E%7B2%7D%20%2B%20%281-4%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B%28-3%29%5E%7B2%7D%2B%28-3%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B9%2B9%7D%3D%5Csqrt%7B18%7D%20%3D%203%5Csqrt%7B2%7D)
=> NP = ![\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-7-%28-3%29%5D%5E%7B2%7D%20%2B%20%281-0%29%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B%28-4%29%5E%7B2%7D%2B1%5E%7B2%7D%20%20%7D%20%3D%20%5Csqrt%7B16%2B1%7D%3D%5Csqrt%7B17%7D)
It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP
=> They are congruent triangles